Concept explainers
Interpretation:
From the given options, one which describes the three core concepts of collision theory has to be identified.
Concept Introduction:
Collision theory:
Collision theory explains why different reactions occurs at different rates. It is used to explain or predict the rate of a reaction. For a
Molecular Collisions:
For a chemical reaction to happen, the molecule must collide with each other. Most of the reactions are carried out in liquid or gaseous state. In liquid and gaseous state, molecules are free to move which makes the collision easier. Solid reactant can also undergo collisions but the problem is only molecules present on the surface can participate in collision. More they collide, more will be the
Activation Energy:
For a reaction to occur, the reactant molecules must collide with some minimum amount of energy. This minimum amount of energy for a reaction to occur is known as activation energy. Every reaction will have different activation energy. Activation energy is dependent on temperature. As the temperature increases, molecules will move faster and the activation energy decreases.
Collision Orientation:
Reactants must be oriented in a way such that the collisions become effective and leads to product formation. Collision orientation is a factor which determines the reaction for non-spherical molecules or atoms.
Example:
In this reaction, the double bond is converted to single bond. Hydrogen atom is attached to one of the carbon and chlorine to the other carbon. The reaction will happen only if hydrogen approaches the carbon-carbon double bond. High concentration of negative charge will be there on the double bond. Chlorine atom is also partially negative, so here the way they hit each other ie, the orientation will determine the reaction.
Want to see the full answer?
Check out a sample textbook solutionChapter 9 Solutions
Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card
- 7. Draw the Lewis structures and molecular orbital diagrams for CO and NO. What are their bond orders? Are the molecular orbital diagrams similar to their Lewis structures? Explain. CO Lewis Structure NO Lewis Structure CO Bond Order NO Bond Order CO Molecular Orbital Diagram NO Molecular Orbital Diagramarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardDraw the condensed structure of 4-ethyl-1,2,4-trifluoro-2-methyloctane.arrow_forward
- 5. The existence of compounds of the noble gases was once a great surprise and stimulated a great deal of theoretical work. Label the molecular orbital diagram for XeF (include atom chemical symbol, atomic orbitals, and molecular orbitals) and deduce its ground state electron configuration. Is XeF likely to have a shorter bond length than XeF+? XeF XeF+ Bond Orderarrow_forwardDon't used hand raitingarrow_forward4. The superoxide ion, Oz, plays an important role in the ageing processes that take place in organisms. Judge whether O2 is likely to have larger or smaller dissociation energy than O2. Molecular Orbital Diagram 8 02 02 Does O2 have larger or smaller dissociation energy?: Bond Orderarrow_forward
- Will a weak base with a pKa of 8.4 be best absorbed in the stomach or the intestine? Explain your reasoning behind your answer. Use a chemical equilibrium equation in your answer.arrow_forwardYou have started a patient on a new drug. Each dose introduces 40 pg/mL of drug after redistribution and prior to elimination. This drug is administered at 24 h intervals and has a half life of 24 h. What will the concentration of drug be after each of the first six doses? Show your work a. What is the concentration after the first dose? in pg/mL b. What is the concentration after the second dose? in pg/mL c. What is the concentration after the third dose? in pg/mLarrow_forwardHow many different molecules are drawn below?arrow_forward
- Only 100% sure experts solve it correct complete solutions need to get full marks it's my quiz okkkk.take your time but solve full accurate okkk chemistry expert solve it.qno4arrow_forwardNonearrow_forwardA complete tensile test was performed on a magnesium specimen of 12 mm diameter and 30 mm length, until breaking. The specimen is assumed to maintain a constant volume. Calculate the approximate value of the actual stress at breaking. TABLE. The tensile force F and the length of the specimen are represented for each L until breaking. F/N L/mm 0 30,0000 30,0296 5000 10000 30,0592 15000 30,0888 20000 30,15 25000 30,51 26500 30,90 27000 31,50 26500 32,10 25000 32,79arrow_forward
- Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co