Essentials of Biology (5th International Edition)
5th Edition
ISBN: 9781259660269
Author: Sylvia S. Mader, Dr., Michael Windelspecht
Publisher: Mcgraw-Hill
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Chapter 9.4, Problem 1LO
Summary Introduction
To determine:
The term non disjunction and how it is responsible for the formation of abnormal chromosomal number.
Introduction:
Humans cell contain 46 chromosomes (2n) and these are diploid in nature but at the time of fertilization only 23 (n) chromosomes are received from mother and 23 (n) chromosomes are received from father to form a zygote by the process of meiosis.
Zygote is formed by the transfer of male gamete (sperm) and female gamete (ova). The ova and sperm are haploid (n) and form a diploid zygote (2n). Zygote receives 46 chromosomes. Some humans are born with abnormalities as they receive abnormal chromosomal number in their cell. Abnormal chromosome is formed when chromosome fails to separate during meiosis and is known as non-disjunction.
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Students have asked these similar questions
19. On the diagram below
a. Label the three pictures as: DNA; polypeptide; or RNA.
b. Label the arrows as: translation or transcription/RNA processing.
c. Add the following details to the diagram.
Promoter region
TATA box
Transcription start site
Transcription terminator
Intron (A,B,C,D)
Exons (1,2,3,4,5)
Splice sites
5' cap
5' UTR (untranslated region)
3' poly A tail
3' UTR (untranslated region)
Translational start (AUG)
Translational stop (UGA, UAG, or UAA)
N and C ends of polypeptide
0000
Match the letter labels in the figure below to the terms. Some letter
labels are not used.
MNNNNNNIN
M
C
B
A
M
D
F
E
H
K
G
8
The diagram below illustrates a quorum sensing pathway from Staphylococcus aureus. Please answer the following questions.
1. Autoinduction is part of the quorum sensing system. Which promoter (P2 or P3) is critical for autoinduction?
2)This staphylococcus aureus grows on human wounds, causing severe infections. You would like to start a clinical trial to treat these wound infections. Please describe:
a) What molecule do you recommend for the trial. Why?
b) Your trial requires that Staphylococcus aureus be isolated from the wound and submitted to genome sequencing before admittance. Why? What are you testing for?
3) If a mutation arises where the Promoter P3 is constitutively active, how would that influence sensitivity to AIP? Please explain your rationale.
4) This pathway is sensitive to bacterial cell density. Describe two separate mutation that would render the pathway active independent of cell density. Briefly explain your rationale.
Mutation 1
Mutation 2
Chapter 9 Solutions
Essentials of Biology (5th International Edition)
Ch. 9.1 - Explain the purpose of meiosisCh. 9.1 - Prob. 2LOCh. 9.1 - Prob. 3LOCh. 9.1 - Prob. 4LOCh. 9.1 - Prob. 1CYPCh. 9.1 - Prob. 2CYPCh. 9.1 - Prob. 3CYPCh. 9.1 - Prob. 4CYPCh. 9.1 - Prob. 1ACh. 9.1 - Prob. 2A
Ch. 9.2 - List the phases of meiosis, and briefly describe...Ch. 9.2 - Prob. 2LOCh. 9.2 - Prob. 1CYPCh. 9.2 - Prob. 2CYPCh. 9.2 - Prob. 3CYPCh. 9.2 - Prob. 3ACh. 9.2 - Prob. 4ACh. 9.2 - Prob. 5ACh. 9.2 - Prob. 6ACh. 9.2 - Prob. 7ACh. 9.2 - Prob. 8ACh. 9.2 - Prob. 9ACh. 9.2 - Prob. 10ACh. 9.2 - Prob. 11ACh. 9.3 - Contrast the events of meiosis I and meiosis II...Ch. 9.3 - Prob. 2LOCh. 9.3 - Prob. 1CYPCh. 9.3 - Prob. 2CYPCh. 9.3 - Summarize the major differences among the stages...Ch. 9.3 - Prob. 12ACh. 9.3 - Prob. 13ACh. 9.3 - Prob. 14ACh. 9.4 - Prob. 1LOCh. 9.4 - Prob. 2LOCh. 9.4 - Prob. 3LOCh. 9.4 - Describe how a zygote can receive an abnormal...Ch. 9.4 - Contrast monosomy with trisomy.Ch. 9.4 - Prob. 3CYPCh. 9.4 - Prob. 15ACh. 9.4 - Prob. 16ACh. 9 - Prob. 1BYBCh. 9 - Prob. 2BYBCh. 9 - Prob. 3BYBCh. 9 - Prob. S4.4BYBCh. 9 - Section 8.2 What events occur during prophase,...Ch. 9 - Prob. S8.2BYBCh. 9 - Although most men with Klinefelter syndrome are...Ch. 9 - Prob. 2TCCh. 9 - Prob. 3TC
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