
EBK VECTOR MECHANICS FOR ENGINEERS: STA
12th Edition
ISBN: 8220106797068
Author: BEER
Publisher: YUZU
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 9.3, Problem 9.74P
To determine
Find the product of inertia of the area with respect to x and y axes by using parallel axis theorem.
Expert Solution & Answer

Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
I need help with a MATLAB code. This code just keeps running and does not give me any plots. I even reduced the tolerance from 1e-9 to 1e-6. Can you help me fix this? Please make sure your solution runs.
% Initial Conditions
rev = 0:0.001:2;
g1 = deg2rad(1);
g2 = deg2rad(3);
g3 = deg2rad(6);
g4 = deg2rad(30);
g0 = deg2rad(0);
Z0 = 0;
w0 = [0; Z0*cos(g0); -Z0*sin(g0)];
Z1 = 5;
w1 = [0; Z1*cos(g1); -Z1*sin(g1)];
Z2 = 11;
w2 = [0; Z2*cos(g2); -Z2*sin(g2)];
[v3, psi3, eta3] = Nut_angle(Z2, g2, w2);
plot(v3, psi3)
function dwedt = K_DDE(~, w_en)
% Extracting the initial condtions to a variable
% Extracting the initial condtions to a variable
w = w_en(1:3);
e = w_en(4:7);
Z = w_en(8);
I = 0.060214;
J = 0.015707;
x = (J/I) - 1;
y = Z - 1;
s = Z;
% Kinematic Differential Equations
dedt = zeros(4,1);
dedt(1) = pi*(e(3)*(s-w(2)-1) + e(2)*w(3) + e(4)*w(1));
dedt(2) = pi*(e(4)*(w(2)-1-s) + e(3)*w(1) - e(1)*w(3));
dedt(3) = pi*(-e(1)*(s-w(2)-1) - e(2)*w(1) + e(4)*w(3));…
alpha 1 is not zero
alpha 1 can equal alpha 2
use velocity triangle to solve for alpha 1
USE MATLAB ONLY
provide typed code
solve for velocity triangle and dont provide copied answer
Turbomachienery .
GIven:
vx = 185 m/s, flow angle = 60 degrees, (leaving a stator in axial flow) R = 0.5, U = 150 m/s, b2 = -a3, a2 = -b3
Find: velocity triangle , a. magnitude of abs vel leaving rotor (m/s) b. flow absolute angles (a1, a2, a3) 3. flow rel angles (b2, b3) d. specific work done e. use code to draw vel. diagram
Use this code for plot
% plots Velocity Tri. in Ch4
function plotveltri(al1,al2,al3,b2,b3)
S1L = [0 1];
V1x = [0 0];
V1s = [0 1*tand(al3)];
S2L = [2 3];
V2x = [0 0];
V2s = [0 1*tand(al2)];
W2s = [0 1*tand(b2)];
U2x = [3 3];
U2y = [1*tand(b2) 1*tand(al2)];
S3L = [4 5];
V3x = [0 0];
V3r = [0 1*tand(al3)];
W3r = [0 1*tand(b3)];
U3x = [5 5];
U3y = [1*tand(b3) 1*tand(al3)];
plot(S1L,V1x,'k',S1L,V1s,'r',...
S2L,V2x,'k',S2L,V2s,'r',S2L,W2s,'b',U2x,U2y,'g',...…
3. Find a basis of eigenvectors and diagonalize.
4
0
-19
7
a.
b.
1-42
16
12-20
[21-61
Chapter 9 Solutions
EBK VECTOR MECHANICS FOR ENGINEERS: STA
Ch. 9.1 - 9.1 through 9.4 Determine by direct integration...Ch. 9.1 - 9.1 through 9.4 Determine by direct integration...Ch. 9.1 - 9.1 through 9.4 Determine by direct integration...Ch. 9.1 - 9.1 through 9.4 Determine by direct integration...Ch. 9.1 - 9.5 through 9.8 Determine by direct integration...Ch. 9.1 - 9.5 through 9.8 Determine by direct integration...Ch. 9.1 - 9.5 through 9.8 Determine by direct integration...Ch. 9.1 - 9.5 through 9.8 Determine by direct integration...Ch. 9.1 - 9.9 through 9.11 Determine by direct integration...Ch. 9.1 - 9.9 through 9.11 Determine by direct integration...
Ch. 9.1 - 9.9 through 9.11 Determine by direct integration...Ch. 9.1 - 9.12 through 9.14 Determine by direct integration...Ch. 9.1 - Prob. 9.13PCh. 9.1 - 9.12 through 9.14 Determine by direct integration...Ch. 9.1 - 9.15 and 9.16 Determine the moment of inertia and...Ch. 9.1 - Prob. 9.16PCh. 9.1 - 9.17 and 9.18 Determine the moment of inertia and...Ch. 9.1 - Prob. 9.18PCh. 9.1 - Determine the moment of inertia and the radius of...Ch. 9.1 - Prob. 9.20PCh. 9.1 - Prob. 9.21PCh. 9.1 - Determine the polar moment of inertia and the...Ch. 9.1 - 9.23 and 9.24 Determine the polar moment of...Ch. 9.1 - 9.23 and 9.24 Determine the polar moment of...Ch. 9.1 - (a) Determine by direct integration the polar...Ch. 9.1 - (a) Show that the polar radius of gyration kQ of...Ch. 9.1 - Determine the polar moment of inertia and the...Ch. 9.1 - Determine the polar moment of inertia and the...Ch. 9.1 - Using the polar moment of inertia of the isosceles...Ch. 9.1 - Prove that the centroidal polar moment of inertia...Ch. 9.2 - 9.31 and 9.32 Determine the moment of inertia and...Ch. 9.2 - 9.31 and 9.32 Determine the moment of inertia and...Ch. 9.2 - 9.33 and 9.34 Determine the moment of inertia and...Ch. 9.2 - 9.33 and 9.34 Determine the moment of inertia and...Ch. 9.2 - Prob. 9.35PCh. 9.2 - Determine the moments of inertia of the shaded...Ch. 9.2 - Prob. 9.37PCh. 9.2 - Fig. P9.37 and P9.38 9.38 Knowing that the shaded...Ch. 9.2 - Prob. 9.39PCh. 9.2 - Fig. P9.39 and P9.40 9.40 The polar moments of...Ch. 9.2 - Prob. 9.41PCh. 9.2 - 9.41 through 9.44 Determine the moments of inertia...Ch. 9.2 - 9.41 through 9.44 Determine the moments of inertia...Ch. 9.2 - 9.41 through 9.44 Determine the moments of inertia...Ch. 9.2 - 9.45 and 9.46 Determine the polar moment of...Ch. 9.2 - 9.45 and 9.46 Determine the polar moment of...Ch. 9.2 - Prob. 9.47PCh. 9.2 - Prob. 9.48PCh. 9.2 - Prob. 9.49PCh. 9.2 - Prob. 9.50PCh. 9.2 - Four L3 3 14 - in. angles are welded to a rolled...Ch. 9.2 - Two 20-mm steel plates are welded to a rolled S...Ch. 9.2 - A channel and a plate are welded together as shown...Ch. 9.2 - The strength of the rolled W section shown is...Ch. 9.2 - Two L76 76 6.4-mm angles are welded to a C250 ...Ch. 9.2 - Two steel plates are welded to a rolled W section...Ch. 9.2 - 9.57 and 9.58 The panel shown forms the end of a...Ch. 9.2 - 9.57 and 9.58 The panel shown forms the end of a...Ch. 9.2 - 9.59 and 9.60 The panel shown forms the end of a...Ch. 9.2 - 9.59 and 9.60 The panel shown forms the end of a...Ch. 9.2 - A vertical trapezoidal gate that is used as an...Ch. 9.2 - The cover for a 0.5-m-diameter access hole in a...Ch. 9.2 - Determine the x coordinate of the centroid of the...Ch. 9.2 - Determine the x coordinate of the centroid of the...Ch. 9.2 - Show that the system of hydrostatic forces acting...Ch. 9.2 - Show that the resultant of the hydrostatic forces...Ch. 9.3 - 9.67 through 9.70 Determine by direct integration...Ch. 9.3 - 9.67 through 9.70 Determine by direct integration...Ch. 9.3 - 9.67 through 9.70 Determine by direct integration...Ch. 9.3 - Prob. 9.70PCh. 9.3 - 9.71 through 9.74 Using the parallel-axis theorem,...Ch. 9.3 - 9.71 through 9.74 Using the parallel-axis theorem,...Ch. 9.3 - 9.71 through 9.74 Using the parallel-axis theorem,...Ch. 9.3 - Prob. 9.74PCh. 9.3 - 9.75 through 9.78 Using the parallel-axis theorem,...Ch. 9.3 - 9.75 through 9.78 Using the parallel-axis theorem,...Ch. 9.3 - 9.75 through 9.78 Using the parallel-axis theorem,...Ch. 9.3 - Prob. 9.78PCh. 9.3 - Determine for the quarter ellipse of Prob. 9.67...Ch. 9.3 - Determine the moments of inertia and the product...Ch. 9.3 - Determine the moments of inertia and the product...Ch. 9.3 - 9.75 through 9.78 Using the parallel-axis theorem,...Ch. 9.3 - Determine the moments of inertia and the product...Ch. 9.3 - Determine the moments of inertia and the product...Ch. 9.3 - Prob. 9.85PCh. 9.3 - 9.86 through 9.88 For the area indicated,...Ch. 9.3 - 9.86 through 9.88 For the area indicated,...Ch. 9.3 - 9.86 through 9.88 For the area indicated,...Ch. 9.3 - 9.89 and 9.90 For the angle cross section...Ch. 9.3 - 9.89 and 9.90 For the angle cross section...Ch. 9.4 - Using Mohrs circle, determine for the quarter...Ch. 9.4 - Using Mohrs circle, determine the moments of...Ch. 9.4 - Using Mohrs circle, determine the moments of...Ch. 9.4 - Using Mohrs circle, determine the moments of...Ch. 9.4 - Using Mohrs circle, determine the moments of...Ch. 9.4 - Using Mohrs circle, determine the moments of...Ch. 9.4 - For the quarter ellipse of Prob. 9.67, use Mohrs...Ch. 9.4 - Prob. 9.98PCh. 9.4 - 9.98 though 9.102 Using Mohrs circle, determine...Ch. 9.4 - 9.98 though 9.102 Using Mohrs circle, determine...Ch. 9.4 - 9.98 through 9.102 Using Mohrs circle, determine...Ch. 9.4 - 9.98 through 9.102 Using Mohrs circle, determine...Ch. 9.4 - Prob. 9.103PCh. 9.4 - 9.104 and 9.105 Using Mohrs circle, determine the...Ch. 9.4 - 9.104 and 9.105 Using Mohrs circle, determine the...Ch. 9.4 - Prob. 9.106PCh. 9.4 - it is known that for a given area Iy = 48 106 mm4...Ch. 9.4 - Prob. 9.108PCh. 9.4 - Using Mohrs circle, prove that the expression...Ch. 9.4 - Using the invariance property established in the...Ch. 9.5 - A thin plate with a mass m is cut in the shape of...Ch. 9.5 - A ring with a mass m is cut from a thin uniform...Ch. 9.5 - Prob. 9.113PCh. 9.5 - The parabolic spandrel shown was cut from a thin,...Ch. 9.5 - Prob. 9.115PCh. 9.5 - Fig. P9.115 and P9.116 9.116 A piece of thin,...Ch. 9.5 - A thin plate of mass m is cut in the shape of an...Ch. 9.5 - Prob. 9.118PCh. 9.5 - Prob. 9.119PCh. 9.5 - The area shown is revolved about the x axis to...Ch. 9.5 - Prob. 9.121PCh. 9.5 - Determine by direct integration the mass moment of...Ch. 9.5 - Fig. P9.122 and P9.123 9.123 Determine by direct...Ch. 9.5 - Determine by direct integration the mass moment of...Ch. 9.5 - Prob. 9.125PCh. 9.5 - A thin steel wire is bent into the shape shown....Ch. 9.5 - Shown is the cross section of an idler roller....Ch. 9.5 - Shown is the cross section of a molded flat-belt...Ch. 9.5 - Prob. 9.129PCh. 9.5 - Knowing that the thin cylindrical shell shown has...Ch. 9.5 - A circular hole of radius r is to be drilled...Ch. 9.5 - Prob. 9.132PCh. 9.5 - After a period of use, one of the blades of a...Ch. 9.5 - Determine the mass moment of inertia of the 0.9-lb...Ch. 9.5 - 9.135 and 9.136 A 2-mm thick piece of sheet steel...Ch. 9.5 - 9.135 and 9.136 A 2 -mm thick piece of sheet steel...Ch. 9.5 - Prob. 9.137PCh. 9.5 - A section of sheet steel 0.03 in. thick is cut and...Ch. 9.5 - Prob. 9.139PCh. 9.5 - Prob. 9.140PCh. 9.5 - The machine element shown is fabricated from...Ch. 9.5 - Determine the mass moments of inertia and the...Ch. 9.5 - Determine the mass moment of inertia of the steel...Ch. 9.5 - Fig. P9.143 and P9.144 9.144 Determine the mass...Ch. 9.5 - Determine the mass moment of inertia of the steel...Ch. 9.5 - Aluminum wire with a weight per unit length of...Ch. 9.5 - The figure shown is formed of 18-in.-diameter...Ch. 9.5 - A homogeneous wire with a mass per unit length of...Ch. 9.6 - Determine the mass products of inertia Ixy, Iyz,...Ch. 9.6 - Determine the mass products of inertia Ixy, Iyz,...Ch. 9.6 - Determine the mass products of inertia Ixy, Iyz,...Ch. 9.6 - Determine the mass products of inertia Ixy, Iyz,...Ch. 9.6 - Prob. 9.153PCh. 9.6 - Prob. 9.154PCh. 9.6 - 9.153 through 9.156 A section of sheet steel 2 mm...Ch. 9.6 - 9.153 through 9.156 A section of sheet steel 2 mm...Ch. 9.6 - The figure shown is formed of 1.5-mm-diameter...Ch. 9.6 - Prob. 9.158PCh. 9.6 - 9.159 and 9.160 Brass wire with a weight per unit...Ch. 9.6 - Fig. P9.160 9.159 and 9.160 Brass wire with a...Ch. 9.6 - Complete the derivation of Eqs. (9.47) that...Ch. 9.6 - Prob. 9.162PCh. 9.6 - Prob. 9.163PCh. 9.6 - Prob. 9.164PCh. 9.6 - Shown is the machine element of Prob. 9.141....Ch. 9.6 - Determine the mass moment of inertia of the steel...Ch. 9.6 - The thin, bent plate shown is of uniform density...Ch. 9.6 - A piece of sheet steel with thickness t and...Ch. 9.6 - Determine the mass moment of inertia of the...Ch. 9.6 - 9.170 through 9.172 For the wire figure of the...Ch. 9.6 - Prob. 9.171PCh. 9.6 - 9.172 Prob. 9.146 9.146 Aluminum wire with a...Ch. 9.6 - For the homogeneous circular cylinder shown with...Ch. 9.6 - For the rectangular prism shown, determine the...Ch. 9.6 - Prob. 9.175PCh. 9.6 - Prob. 9.176PCh. 9.6 - Consider a cube with mass m and side a. (a) Show...Ch. 9.6 - Prob. 9.178PCh. 9.6 - Prob. 9.179PCh. 9.6 - 9.180 through 9.184 For the component described in...Ch. 9.6 - 9.180 through 9.184 For the component described in...Ch. 9.6 - Prob. 9.182PCh. 9.6 - 9.180 through 9.184 For the component described in...Ch. 9.6 - 9.180 through 9.184 For the component described in...Ch. 9 - Determine by direct integration the moments of...Ch. 9 - Determine the moment of inertia and the radius of...Ch. 9 - Determine the moment of inertia and the radius of...Ch. 9 - Determine the moments of inertia Ix and Iy of the...Ch. 9 - Determine the polar moment of inertia of the area...Ch. 9 - Two L4 4 12-in. angles are welded to a steel...Ch. 9 - Using the parallel-axis theorem, determine the...Ch. 9 - Prob. 9.192RPCh. 9 - Fig. P9.193 and P9.194 9.193 A thin plate with a...Ch. 9 - Fig. P9.193 and P9.194 9.194 A thin plate with...Ch. 9 - A 2-mm-thick piece of sheet steel is cut and bent...Ch. 9 - Determine the mass moment of inertia of the steel...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- 2. Find the eigenvalues. Find the corresponding eigenvectors. 6 2 -21 [0 -3 1 3 31 a. 2 5 0 b. 3 0 -6 C. 1 1 0 -2 0 7 L6 6 0 1 1 2. (Hint: λ = = 3)arrow_forwardUSE MATLAB ONLY provide typed code solve for velocity triangle and dont provide copied answer Turbomachienery . GIven: vx = 185 m/s, flow angle = 60 degrees, (leaving a stator in axial flow) R = 0.5, U = 150 m/s, b2 = -a3, a2 = -b3 Find: velocity triangle , a. magnitude of abs vel leaving rotor (m/s) b. flow absolute angles (a1, a2, a3) 3. flow rel angles (b2, b3) d. specific work done e. use code to draw vel. diagram Use this code for plot % plots Velocity Tri. in Ch4 function plotveltri(al1,al2,al3,b2,b3) S1L = [0 1]; V1x = [0 0]; V1s = [0 1*tand(al3)]; S2L = [2 3]; V2x = [0 0]; V2s = [0 1*tand(al2)]; W2s = [0 1*tand(b2)]; U2x = [3 3]; U2y = [1*tand(b2) 1*tand(al2)]; S3L = [4 5]; V3x = [0 0]; V3r = [0 1*tand(al3)]; W3r = [0 1*tand(b3)]; U3x = [5 5]; U3y = [1*tand(b3) 1*tand(al3)]; plot(S1L,V1x,'k',S1L,V1s,'r',... S2L,V2x,'k',S2L,V2s,'r',S2L,W2s,'b',U2x,U2y,'g',... S3L,V3x,'k',S3L,V3r,'r',S3L,W3r,'b',U3x,U3y,'g',...... 'LineWidth',2,'MarkerSize',10),...…arrow_forwardUSE MATLAB ONLY provide typed code solve for velocity triangle and dont provide copied answer Turbomachienery . GIven: vx = 185 m/s, flow angle = 60 degrees, R = 0.5, U = 150 m/s, b2 = -a3, a2 = -b3 Find: velocity triangle , a. magnitude of abs vel leaving rotor (m/s) b. flow absolute angles (a1, a2, a3) 3. flow rel angles (b2, b3) d. specific work done e. use code to draw vel. diagram Use this code for plot % plots Velocity Tri. in Ch4 function plotveltri(al1,al2,al3,b2,b3) S1L = [0 1]; V1x = [0 0]; V1s = [0 1*tand(al3)]; S2L = [2 3]; V2x = [0 0]; V2s = [0 1*tand(al2)]; W2s = [0 1*tand(b2)]; U2x = [3 3]; U2y = [1*tand(b2) 1*tand(al2)]; S3L = [4 5]; V3x = [0 0]; V3r = [0 1*tand(al3)]; W3r = [0 1*tand(b3)]; U3x = [5 5]; U3y = [1*tand(b3) 1*tand(al3)]; plot(S1L,V1x,'k',S1L,V1s,'r',... S2L,V2x,'k',S2L,V2s,'r',S2L,W2s,'b',U2x,U2y,'g',... S3L,V3x,'k',S3L,V3r,'r',S3L,W3r,'b',U3x,U3y,'g',...... 'LineWidth',2,'MarkerSize',10),... axis([-1 6 -4 4]), ...…arrow_forward
- The answer should equal to 1157. Please sent me the solution. Thank you!arrow_forwardBONUS: If the volume of the 8cm x 6.5cm x 6cm Block of Aluminum was 312cm3 before machining, find how much material was removed when the fixture below was machined. +2 2.00 cm 6.00 cm 2.50 cm 6.50 cm 1.00 cm 2.50 cm 11.00 cm 8.00 cm 30 CP 9411 FL.4) (m² 1157 Area of triangle = 1/2*B*H Area of circle = лR² Circumference of a circle = 2πR 6.00 cm 6.50 cm 1.50 cm Radius 1.50 cm 1.00 cmarrow_forwardConsider a 5m by 5m wet concret patio with an average water film thickness of .2mm. Now wind at 50 km/h is blowing over the surface. If the air is at 1 atm, 15oC and 35 percent relative humidity, determine how long it will take for the patio to completely dry.arrow_forward
- 70. Compute the number of cubic centimeters of iron required for the cast-iron plate shown. The plate is 3.50 centimeters thick. Round the answer to the nearest cubic centimeter. 50.0 cm 40.0 cm Radius 150° 115.0 cm- 81.0 cmarrow_forwardLaw of Sines Solve the following problems using the Law of Sin 7. Find side x. All dimensions are in inches. -°-67°-37° 81° x Sin A 8.820 X 67°00' 32°00' a sin A b C sin B sin Carrow_forward35. a. Determine B. b. Determine side b. c. Determine side c. 5.330 in.- ZB 73°30'arrow_forward
- Consider a 12 cm internal diameter, 14 m long circular duct whose interior surface is wet. The duct is to be dried by forcing dry air at 1 atm and 15 degrees C throught it at an average velocity of 3m/s. The duct passes through a chilled roo, and it remains at an average temp of 15 degrees C at all time. Determine the mass transfer coeeficient in the duct.arrow_forwardnote n=number of link(dont include the ground link (fixed))arrow_forward6.(单选题) The DOF of the following mechanism is E A F=3x4-2x5-0=2 B F=3x3-2x4-0=1 F=3x3-2x3-2=1 D F=3x4-2x5-1=1arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University PressMechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSONThermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
- Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEYMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage LearningEngineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY

Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press

Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON

Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education

Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY

Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning

Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
moment of inertia; Author: NCERT OFFICIAL;https://www.youtube.com/watch?v=A4KhJYrt4-s;License: Standard YouTube License, CC-BY