Statics and Mechanics of Materials (5th Edition)
5th Edition
ISBN: 9780134382593
Author: Russell C. Hibbeler
Publisher: PEARSON
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Textbook Question
Chapter 9.2, Problem 4P
The composite shaft, consisting of aluminum, copper, and steel sections, is subjected to the loading shown. Determine the displacement of B with respect to C. The cross-sectional area and modulus of elasticity for each section are shown in the figure. Neglect the size of the collars at B and C.
| Aluminum | Copper | Steel |
| Eal = 10(103) ksi | Ecu = 18(103) ksi | Est =29(103) ksi |
| AAB = 0.09 in2 | ABC = 0.12 in2 | ACD = 0.06 in2 |
Probs. 9-3/4
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1.
The composite shaft, consisting of aluminum, copper,
and steel sections, is subjected to the loading shown.
Determine the displacement of B with respect to C and the
normal stress in each section. The cross-sectional area and
modulus of elasticity for each section are shown in the figure.
Neglect the size of the collars at B and C.
Aluminum
Eal = 70 GPa
AAB = 58 mm²
9 kN
A
Copper
Ecu = 126 GPa
ABC = 77 mm²
450 mm
16 kN
斤。
16 kN
-300 mm
BL
Steel
Est = 200 GPa
ACD = 39 mm²
8 kN
8 kN
-400 mm
7 kN
The
The composite shaft, consisting of aluminum, copper, and steel sections, is
subjected to the loading shown. The cross-sectional area and modulus of elasticity for each
orl section are shown in the figure. The material of section AB, BC, and CD is aluminum, copper,
and steel, respectively. Neglect the size of the collars at B and C. Determine (a) the
displacement of end A with respect to end D, (b) the displacement of end B with respect to end
C, and (c) the normal stress in each section.
Aluminum
Соpper
Steel
Ea = 10(103) ksi
AAB= 0.09 in?
Ecu = 18(10') ksi
ABC = 0.12 in?
E = 29(103) ksi
Acd = 0.06 in²
%3D
3.50 kip
1.75 kip
2.00 kip
1.50 kip
A
B
3.50 kip
1.75 kip
-18 in.-
-12 in.-
-16 in.-
urses
This course
EHide blocks
OP=294 N
O P = 235 N
Let's consider a rod having a solid circular cross-section with diameter of 5 mm and it is made of a material having a
Young's modulus E = 120 Gpa and a Poisson's ratio of 0.33. If a tensile force Fis subjected to that rod cross-section, the
diameter becomes 4.998 mm. determine the applied force F.
Select one:
O a. F= 3427 N
O b. F = 8568 N
O C.F= 2285 N
O d. F= 7140 N
O e. F = 5712 N
O f.F= 2856 N
Finish attempt ...
Chapter 9 Solutions
Statics and Mechanics of Materials (5th Edition)
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