Explanation Procedure used: 1. Place the vector A such that θ is in standard position. 2. Calculate A x and A y from A x = A cos θ and A y = A sin θ . Use the reference angle if the direction of the component is noted. 3. Check the components to see if each is in the correct direction and has a magnitude that is proper for the reference angle. Calculation: Given that, the one of the pull makes 18 ° with the center of the canal with a force 760 N. The force of the other pull is 820 N. Note that, the x- and y- components are vectores directed along the axes that, when added together, equal the given vector. The y components of the pull’s must have same magnitude and opposite directions. The y- component F y of the first pull is equal to the y- component F y of the second pull

11th Edition

ISBN: 9780134508290

Author: Evans

Publisher: PEARSON CUSTOM PUB.(CONSIGNMENT)

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Chapter 9.2, Problem 27E

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The angle makes the other pull to moves down the center of the canal with a force 820 N.

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Chapter 9.2, Problem 26E

Chapter 9.2, Problem 28E

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Chapter 9 Solutions

EBK BASIC TECHNICAL MATHEMATICS

Ch. 9.1 - For the vectors in Example 2, show that R = B + C...Ch. 9.1 - Prob. 2PE Ch. 9.1 - Prob. 1E Ch. 9.1 - Prob. 2E Ch. 9.1 - Prob. 3E Ch. 9.1 - Prob. 4E Ch. 9.1 - Prob. 5E Ch. 9.1 - Prob. 6E Ch. 9.1 - Prob. 7E Ch. 9.1 - Prob. 8E

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