Explanation Formula used: For any triangle with sides a, b and c , opposite angles A , B and C respectively, the law of Cosines and law of Sines can be defined as follows. Law of cosines: a 2 = b 2 + c 2 − 2 b c cos A This can be also written as follows. b 2 = a 2 + c 2 − 2 a c cos B c 2 = a 2 + b 2 − 2 a b cos C Law of sines: a sin A = b sin B = c sin C Calculation: Given that, the magnitude of b = 7607 , c = 4053 and B = 110.09 ° . Sketch the graph of the triangle with known measures as shown below in Figure 1. From Figure 1, it is observed that the two sides and one of the opposite angle of known sideof the triangle is known. Now, use the law of sines and find the C . a sin A = c sin C 7607 sin 110.09 ° = 4053 sin C sin C = 4053 sin 110

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Chapter 9, Problem 27RE

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To solve: The triangle if b=7607,c=4053 and B=110.09°.

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Chapter 9, Problem 26RE

Chapter 9, Problem 28RE

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EBK BASIC TECHNICAL MATHEMATICS

Ch. 9.1 - For the vectors in Example 2, show that R = B + C...Ch. 9.1 - Prob. 2PE Ch. 9.1 - Prob. 1E Ch. 9.1 - Prob. 2E Ch. 9.1 - Prob. 3E Ch. 9.1 - Prob. 4E Ch. 9.1 - Prob. 5E Ch. 9.1 - Prob. 6E Ch. 9.1 - Prob. 7E Ch. 9.1 - Prob. 8E

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The triangle if b = 7607 , c = 4053 and B = 110.09 ° .

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