Explanation Given: The system of equation: { 2 w + x − y = 3 w − 3 x + 2 y = − 4 3 w + x − 3 y + z = 1 w + 2 x − 4 y − z = − 2 Calculation: Consider the system of the equation: { 2 w + x − y = 3 w − 3 x + 2 y = − 4 3 w + x − 3 y + z = 1 w + 2 x − 4 y − z = − 2 The matrix corresponding to the system of equation is as follows: [ 2 1 − 1 0 3 1 − 3 2 0 − 4 3 1 − 3 1 1 1 2 − 4 − 1 − 2 ] Use the elementary row transformation to find the echelon form of the matrix. Interchange R 1 ↔ R 2 [ 1 − 3 2 0 − 4 2 1 − 1 0 3 3 1 − 3 1 1 1 2 − 4 − 1 − 2 ] Apply R 3 → R 3 − 3 R 1 , R 2 → R 2 − 2 R 1 [ 1 − 3 2 0 − 4 0 7 − 5 0 11 0 10 − 9 1 13 1 2 − 4 − 1 − 2 ] Apply R 4 → R 4 − R 1 [ 1 − 3 2 0 − 4 0 7 − 5 0 11 0 10 − 9 1 13 0 5 − 6 − 1 2 ] Apply R 3 → R 3 − 2 R 4 [ 1 − 3 2 0 − 4 0 7 − 5 0 11 0 0 3 3 9 0 5 − 6 − 1 2 ] Interchange R

$ALGREBRA AND TRIG MYLAB W\ETEXT & MYLAB$

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ISBN: 9780137915224

Author: Blitzer

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Chapter 9.2, Problem 11E

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To calculate: The solution to system of equation {2w+x−y=3w−3x+2y=−43w+x−3y+z=1w+2x−4y−z=−2 by the Gaussian elimination.

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Chapter 9.2, Problem 10E

Chapter 9.2, Problem 12E

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Chapter 9 Solutions

ALGREBRA AND TRIG MYLAB W\ETEXT & MYLAB

Ch. 9.1 - Fill in each blank so that the resulting statement...Ch. 9.1 - Fill in each blank so that the resulting statement...Ch. 9.1 - Prob. 3CVC Ch. 9.1 - Prob. 4CVC Ch. 9.1 - Fill in each blank so that the resulting statement...Ch. 9.1 - Fill in each blank so that the resulting statement...Ch. 9.1 - In Exercises 1-8, write the augmented matrix for...Ch. 9.1 - In Exercises 1-8, write the augmented matrix for...Ch. 9.1 - In Exercises 18, write the augmented matrix for...Ch. 9.1 - In Exercises 1-8, write the augmented matrix for...

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The solution to system of equation { 2 w + x − y = 3 w − 3 x + 2 y = − 4 3 w + x − 3 y + z = 1 w + 2 x − 4 y − z = − 2 by the Gaussian elimination.

Solution Summary: The author calculates the solution to the system of equation c2w+x-y=3 by the Gaussian elimination.

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To calculate: The solution to system of equation {2w+x−y=3w−3x+2y=−43w+x−3y+z=1w+2x−4y−z=−2 by the Gaussian elimination.

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Chapter 9 Solutions