Explanation The following figure shows the T - s diagram of the engine. Figure-(1) Write the expression for the reduced pressure at state 5. p ′ r 5 = ( p 5 p 4 ) p ′ r 4 (I) Here, the pressure at state 4 is p 4 , the pressure at state 5 is p 5 , the pressure at state 5 is p 5 , the reduced pressure at state 5 is p ′ r 5 and the reduced pressure at state 4 is p ′ r 4 . Write the expression for the velocity at the nozzle exit. V 5 = 2 ( h ′ 4 − h ′ 5 ) (II) Here, the velocity at the nozzle exit is V 5 , the specific enthalpy at state 4 is h ′ 4 and the specific enthalpy at state 5 is h ′ 5 . Write the expression for force developed. F x = m ( V 5 − V a ) (XII) Here, the initial velocity is V a . Write the expression for thrust force. F t h r u s t = − F x (XIII) Conclusion: Refer to table A-22 “ideal gas properties of air” to obtain the specific enthalpy and reduced pressure at temperature T ′ 4 = 1300 K as 1395.97 kJ / kg and 330.9 . Substitute 163.4 kPa for p 4 , 330.9 for p ′ r 4 and 26 kPa for p 3 in Equation (I). p ′ r 5 = ( 26 kPa 163.4 kPa ) ( 330.9 ) = 0.159118 ( 330.9 ) ≈ 52.652 Refer to table A-22 “ideal gas properties of air” to obtain the specific enthalpy and reduced pressure at temperature T ′ 4 = 1300 K as 1395

Fundamentals of Engineering Thermodynamics

8th Edition

ISBN: 9781118832318

Author: MORAN

Publisher: WILEY

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Chapter 9.14, Problem 106P

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The thrust force developed by the engine.

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Chapter 9.14, Problem 105P

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