Finding general solutions Find the general solution of each differential equation. Use C , C 1 , C 2 , ... to denote arbitrary constants. v ″ ( x ) = 5 x 2
Finding general solutions Find the general solution of each differential equation. Use C , C 1 , C 2 , ... to denote arbitrary constants. v ″ ( x ) = 5 x 2
Solution Summary: The author explains how to find the general solution of the differential equation v′′(x)=5.
Finding general solutions Find the general solution of each differential equation. Use C, C1, C2, ... to denote arbitrary constants.
v
″
(
x
)
=
5
x
2
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
According to Newton's law of universal gravitation, the force F between two bodies of constant mass
GmM
m and M is given by the formula F =
, where G is the gravitational constant and d is the
d²
distance between the bodies.
a. Suppose that G, m, and M are constants. Find the rate of change of force F with respect to
distance d.
F' (d)
2GmM
b. Find the rate of change of force F with gravitational constant G = 6.67 × 10-¹¹ Nm²/kg², on
two bodies 5 meters apart, each with a mass of 250 kilograms. Answer in scientific notation,
rounding to 2 decimal places.
-6.67x10
N/m syntax incomplete.
Chapter 9 Solutions
Calculus: Early Transcendentals, Books a la Carte, and MyLab Math with Pearson eText -- Title-Specific Access Card Package (3rd Edition)
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