Chapter 9, Problem 9.72AP

(a)

Interpretation Introduction

Interpretation:

Mass needed for each of the following ion equivalents has to be identified.

Concept introduction:

• Equivalent mass of the substance is the molecular weight divided by its valency.
• The number of ions that carry 1mol of charge is one equivalent.

$\begin{array}{l}\text{1}\text{mEq}\text{=}\text{0}\text{.001Eq}\\ \text{1}\text{Eq}\text{=}\text{1000}\text{mEq}\end{array}$

• The number of equivalents of a given ion per liter of solution is calculated by multiplying molarity of the ion (moles per liter ) by the charge of the ion.

(b)

Interpretation Introduction

Interpretation:

Mass needed for each of the following ion equivalents has to be identified.

Concept introduction:

• Equivalent mass of the substance is the molecular weight divided by its valency.
• The number of ions that carry 1mol of charge is one equivalent.

$\begin{array}{l}\text{1}\text{mEq}\text{=}\text{0}\text{.001Eq}\\ \text{1}\text{Eq}\text{=}\text{1000}\text{mEq}\end{array}$

• The number of equivalents of a given ion per liter of solution is calculated by multiplying molarity of the ion (moles per liter ) by the charge of the ion.

(c)

Interpretation Introduction

Interpretation:

Mass needed for each of the following ion equivalents has to be identified.

Concept introduction:

• Equivalent mass of the substance is the molecular weight divided by its valency.
• The number of ions that carry 1mol of charge is one equivalent.

$\begin{array}{l}\text{1}\text{mEq}\text{=}\text{0}\text{.001Eq}\\ \text{1}\text{Eq}\text{=}\text{1000}\text{mEq}\end{array}$

• The number of equivalents of a given ion per liter of solution is calculated by multiplying molarity of the ion (moles per liter ) by the charge of the ion.

(d)

Interpretation Introduction

Interpretation:

Mass needed for each of the following ion equivalents has to be identified.

Concept introduction:

• Equivalent mass of the substance is the molecular weight divided by its valency.
• The number of ions that carry 1mol of charge is one equivalent.

$\begin{array}{l}\text{1}\text{mEq}\text{=}\text{0}\text{.001Eq}\\ \text{1}\text{Eq}\text{=}\text{1000}\text{mEq}\end{array}$

• The number of equivalents of a given ion per liter of solution is calculated by multiplying molarity of the ion (moles per liter ) by the charge of the ion.