ector position of a 3.45 g particle moving in the xy plane varies in time according to r₁ = (3î + 3ĵ)t + 2ĵt² where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.65 g particle varies as r₂ = 3î – 2ît² – 6jt. Determine the vector position (in cm) of the center of mass of the system at t = 2.90 s. cm Determine the linear momentum (in g - cm/s) of the system at t = 2.90 s. 9. cm/s 2. p= Determine the velocity (in cm/s) of the center of mass at t = 2.90 s. 7 Vcm = cm/s

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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The vector position of a 3.45 g particle moving in the xy plane varies in time according to r₁ = (3î + 3ĵ)t + 2ĵt² where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.65 g particle varies as r₂ = 3î − 2ît² – 6ĵt.
(a) Determine the vector position (in cm) of the center of mass of the system at t = 2.90 s.
7cm
(b) Determine the linear momentum (in g. cm/s) of the system at t = 2.90 s.
p =
cm
(c) Determine the velocity (in cm/s) of the center of mass at t = 2.90 s.
cm
=
cm
g. cm/s
=
(d) Determine the acceleration (in cm/s2) of the center of mass at t = 2.90 s.
cm/s²
cm/s
(e) Determine the net force (in µN) exerted on the two-particle system at t = 2.90 s.
Fnet
μN
Transcribed Image Text:The vector position of a 3.45 g particle moving in the xy plane varies in time according to r₁ = (3î + 3ĵ)t + 2ĵt² where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.65 g particle varies as r₂ = 3î − 2ît² – 6ĵt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.90 s. 7cm (b) Determine the linear momentum (in g. cm/s) of the system at t = 2.90 s. p = cm (c) Determine the velocity (in cm/s) of the center of mass at t = 2.90 s. cm = cm g. cm/s = (d) Determine the acceleration (in cm/s2) of the center of mass at t = 2.90 s. cm/s² cm/s (e) Determine the net force (in µN) exerted on the two-particle system at t = 2.90 s. Fnet μN
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