The cause for prepared solution concentration is not to be exactly 0.1 M should be found from the given options. Concept introduction: Steps involving standard solution preparation: The steps involving in the preparation of known molar solution using volumetric flask are, The calculated mass of the solute is weighed in the balance and the weighed solute is transferred in to the volumetric flack. Then small quantity of water is added in to the volumetric flack and shaken to dissolve the solute. After dissolving solute particles, water is poured into the volumetric flack to reach the mark. Errors in standard solution preparation: Incorrect weight of solute makes a concentration change in final solution. Loss of solute particles results lower the concentration of final solution. Before the addition of solute, if water is filled in the volumetric flask to reach the mark, the resulting volume changes (increasing of volume) in final solution, this volume changes makes concentration decreases. Neglecting addition of last bit of water into volumetric flask to reach the mark results in lower volume than the calculated volume.

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Answer 1

Question

Chapter 9, Problem 9.3VC

Interpretation Introduction

Interpretation:

The cause for prepared solution concentration is not to be exactly 0.1 M should be found from the given options.

Concept introduction:

Steps involving standard solution preparation:

The steps involving in the preparation of known molar solution using volumetric flask are,

The calculated mass of the solute is weighed in the balance and the weighed solute is transferred in to the volumetric flack. Then small quantity of water is added in to the volumetric flack and shaken to dissolve the solute. After dissolving solute particles, water is poured into the volumetric flack to reach the mark.

Errors in standard solution preparation:

Incorrect weight of solute makes a concentration change in final solution.

Loss of solute particles results lower the concentration of final solution.

Before the addition of solute, if water is filled in the volumetric flask to reach the mark, the resulting volume changes (increasing of volume) in final solution, this volume changes makes concentration decreases.

Neglecting addition of last bit of water into volumetric flask to reach the mark results in lower volume than the calculated volume.

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Answer 2

Question

Chapter 9, Problem 9.3VC

Interpretation Introduction

Interpretation:

The cause for prepared solution concentration is not to be exactly 0.1 M should be found from the given options.

Concept introduction:

Steps involving standard solution preparation:

The steps involving in the preparation of known molar solution using volumetric flask are,

The calculated mass of the solute is weighed in the balance and the weighed solute is transferred in to the volumetric flack. Then small quantity of water is added in to the volumetric flack and shaken to dissolve the solute. After dissolving solute particles, water is poured into the volumetric flack to reach the mark.

Errors in standard solution preparation:

Incorrect weight of solute makes a concentration change in final solution.

Loss of solute particles results lower the concentration of final solution.

Before the addition of solute, if water is filled in the volumetric flask to reach the mark, the resulting volume changes (increasing of volume) in final solution, this volume changes makes concentration decreases.

Neglecting addition of last bit of water into volumetric flask to reach the mark results in lower volume than the calculated volume.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 9, Problem 9.3VC

Interpretation Introduction

Interpretation:

The cause for prepared solution concentration is not to be exactly 0.1 M should be found from the given options.

Concept introduction:

Steps involving standard solution preparation:

The steps involving in the preparation of known molar solution using volumetric flask are,

The calculated mass of the solute is weighed in the balance and the weighed solute is transferred in to the volumetric flack. Then small quantity of water is added in to the volumetric flack and shaken to dissolve the solute. After dissolving solute particles, water is poured into the volumetric flack to reach the mark.

Errors in standard solution preparation:

Incorrect weight of solute makes a concentration change in final solution.

Loss of solute particles results lower the concentration of final solution.

Before the addition of solute, if water is filled in the volumetric flask to reach the mark, the resulting volume changes (increasing of volume) in final solution, this volume changes makes concentration decreases.

Neglecting addition of last bit of water into volumetric flask to reach the mark results in lower volume than the calculated volume.

Expert Solution & Answer

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Answer 4

Question

Chapter 9, Problem 9.3VC

Interpretation Introduction

Interpretation:

The cause for prepared solution concentration is not to be exactly 0.1 M should be found from the given options.

Concept introduction:

Steps involving standard solution preparation:

The steps involving in the preparation of known molar solution using volumetric flask are,

The calculated mass of the solute is weighed in the balance and the weighed solute is transferred in to the volumetric flack. Then small quantity of water is added in to the volumetric flack and shaken to dissolve the solute. After dissolving solute particles, water is poured into the volumetric flack to reach the mark.

Errors in standard solution preparation:

Incorrect weight of solute makes a concentration change in final solution.

Loss of solute particles results lower the concentration of final solution.

Before the addition of solute, if water is filled in the volumetric flask to reach the mark, the resulting volume changes (increasing of volume) in final solution, this volume changes makes concentration decreases.

Neglecting addition of last bit of water into volumetric flask to reach the mark results in lower volume than the calculated volume.

Expert Solution & Answer

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Answer 5

Chapter 9, Problem 9.3VC

Interpretation Introduction

Interpretation:

The cause for prepared solution concentration is not to be exactly 0.1 M should be found from the given options.

Concept introduction:

Steps involving standard solution preparation:

The steps involving in the preparation of known molar solution using volumetric flask are,

The calculated mass of the solute is weighed in the balance and the weighed solute is transferred in to the volumetric flack. Then small quantity of water is added in to the volumetric flack and shaken to dissolve the solute. After dissolving solute particles, water is poured into the volumetric flack to reach the mark.

Errors in standard solution preparation:

Incorrect weight of solute makes a concentration change in final solution.

Loss of solute particles results lower the concentration of final solution.

Before the addition of solute, if water is filled in the volumetric flask to reach the mark, the resulting volume changes (increasing of volume) in final solution, this volume changes makes concentration decreases.

Neglecting addition of last bit of water into volumetric flask to reach the mark results in lower volume than the calculated volume.

Answer 6

Chapter 9, Problem 9.3VC

Interpretation Introduction

Interpretation:

The cause for prepared solution concentration is not to be exactly 0.1 M should be found from the given options.

Concept introduction:

Steps involving standard solution preparation:

The steps involving in the preparation of known molar solution using volumetric flask are,

The calculated mass of the solute is weighed in the balance and the weighed solute is transferred in to the volumetric flack. Then small quantity of water is added in to the volumetric flack and shaken to dissolve the solute. After dissolving solute particles, water is poured into the volumetric flack to reach the mark.

Errors in standard solution preparation:

Incorrect weight of solute makes a concentration change in final solution.

Loss of solute particles results lower the concentration of final solution.

Before the addition of solute, if water is filled in the volumetric flask to reach the mark, the resulting volume changes (increasing of volume) in final solution, this volume changes makes concentration decreases.

Neglecting addition of last bit of water into volumetric flask to reach the mark results in lower volume than the calculated volume.

Answer 7

Chapter 9, Problem 9.3VC

Interpretation Introduction

Interpretation:

The cause for prepared solution concentration is not to be exactly 0.1 M should be found from the given options.

Concept introduction:

Steps involving standard solution preparation:

The steps involving in the preparation of known molar solution using volumetric flask are,

The calculated mass of the solute is weighed in the balance and the weighed solute is transferred in to the volumetric flack. Then small quantity of water is added in to the volumetric flack and shaken to dissolve the solute. After dissolving solute particles, water is poured into the volumetric flack to reach the mark.

Errors in standard solution preparation:

Incorrect weight of solute makes a concentration change in final solution.

Loss of solute particles results lower the concentration of final solution.

Before the addition of solute, if water is filled in the volumetric flask to reach the mark, the resulting volume changes (increasing of volume) in final solution, this volume changes makes concentration decreases.

Neglecting addition of last bit of water into volumetric flask to reach the mark results in lower volume than the calculated volume.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 9.1 - Sports drinks typically contain sucrose...Ch. 9.1 - Prob. 1PPA Ch. 9.1 - Prob. 1PPB Ch. 9.1 - Prob. 1PPC Ch. 9.1 - Prob. 9.1.1SR Ch. 9.1 - Prob. 9.1.2SR Ch. 9.1 - Prob. 9.1.3SR Ch. 9.2 - Classify each of the following compounds as...Ch. 9.2 - Prob. 2PPA Ch. 9.2 - Prob. 2PPB

Solution Summary: The author explains that the cause for prepared solution concentration is not to be exactly 0.1M from the given options.

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