Fundamentals of Aerodynamics
Fundamentals of Aerodynamics
6th Edition
ISBN: 9781259129919
Author: John D. Anderson Jr.
Publisher: McGraw-Hill Education
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Chapter 9, Problem 9.3P

Equation ( 8 . 8 0 ) does not hold for an oblique shock wave, and hence the column in Appendix B labeled p 0 , 2 / p 1 cannot be used, in conjunction with the normal component of the upstream Mach number, to obtain the total pressure behind an oblique shock wave. On the other hand, the column labeled p 0 , 2 / p 0 , 1 can be used for an oblique shock wave, using M n , 1 . Explain why all this is so.

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Example 2. A high-speed AC 130 gunship is flying at a pressure altitude of 10 km. A Pitot tube on the wingtip measures a pressure of 4.24 x 10ª N/m2. Calculate the Mach number at which the aircraft is flying. Solution: Solving for P1 at an altitude of 10000 m, we get 2.65 x 104 N/m2 k-1 1.4-1 Po k 4.24 x 104) 1.4 M? k – 1 - 1 - 1 1.4 – 1 2.65 x 104 M? = 0.719 M1 = 0.848
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3:34 ull Q3.pdf Q1) Air at mach number 2 , pressure 0.5* 10° N/m² and a temperature of 0 °C , over a wedge and generation of an oblique shock wave 40° . determine : 1. Static pressure and temperature downstream the shock. 2. The mach number of the flow downstream the shock. 3. The wedge angle. *********** Q2) As shown in figure (1) A mach number 2.4 air stream at oblique shock angle of (B1-2 =30°) of incident shock with turning angle (0=10°). determine : 1. the mach number of the flow upstream the reflected shock. 2. the mach number of the flow downstream the reflected shock. M2 M3 Figure (1)
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