Modern Database Management
13th Edition
ISBN: 9780134792293
Author: Hoffer
Publisher: PEARSON
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Chapter 9, Problem 9.36PAE
Program Plan Intro
(a)
To construct:
Table for the given transactions assuming the data as transient.
Program Plan Intro
(b)
To construct:
The tables for the given transactions if the data is periodic.
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I need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place.
My code:
% Define frequency range for the plot
f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz
w = 2 * pi * f; % Angular frequency
% Parameters for the filters - let's adjust these to get more reasonable cutoffs
R = 1e3; % Resistance in ohms (1 kΩ)
C = 1e-6; % Capacitance in farads (1 μF)
% For bandpass, we need appropriate L value for desired cutoffs
L = 0.1; % Inductance in henries - adjusted for better bandpass response
% Calculate cutoff frequencies first to verify they're in desired range
f_cutoff_RC = 1 / (2 * pi * R * C);
f_resonance = 1 / (2 * pi * sqrt(L * C));
Q_factor = (1/R) * sqrt(L/C);
f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor));
f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor));
% Transfer functions
% Low-pass filter (RC)
H_low = 1 ./ (1 + 1i * w *…
My code is experincing minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place.
My code:
% Define frequency range for the plot
f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz
w = 2 * pi * f; % Angular frequency
% Parameters for the filters - let's adjust these to get more reasonable cutoffs
R = 1e3; % Resistance in ohms (1 kΩ)
C = 1e-6; % Capacitance in farads (1 μF)
% For bandpass, we need appropriate L value for desired cutoffs
L = 0.1; % Inductance in henries - adjusted for better bandpass response
% Calculate cutoff frequencies first to verify they're in desired range
f_cutoff_RC = 1 / (2 * pi * R * C);
f_resonance = 1 / (2 * pi * sqrt(L * C));
Q_factor = (1/R) * sqrt(L/C);
f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor));
f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor));
% Transfer functions
% Low-pass filter (RC)
H_low = 1 ./ (1 + 1i * w *…
I would like to know the main features about the following three concepts:
1. Default forwarded
2. WINS Server
3. IP Security (IPSec).
Chapter 9 Solutions
Modern Database Management
Ch. 9 - Prob. 9.1RQCh. 9 - Prob. 9.2RQCh. 9 - Prob. 9.3RQCh. 9 - List the five major trends that necessitate data...Ch. 9 - Prob. 9.5RQCh. 9 - Prob. 9.6RQCh. 9 - Prob. 9.7RQCh. 9 - Prob. 9.8RQCh. 9 - Prob. 9.9RQCh. 9 - Prob. 9.10RQ
Ch. 9 - List four objectives of derived data.Ch. 9 - Prob. 9.12RQCh. 9 - Prob. 9.13RQCh. 9 - Explain the pros and cons of logical data marts.Ch. 9 - Prob. 9.15RQCh. 9 - What is a helper table, and why is it often used...Ch. 9 - Describe the characteristics of a surrogate key as...Ch. 9 - Prob. 9.18RQCh. 9 - What is the purpose of conformed dimensions for...Ch. 9 - Prob. 9.20RQCh. 9 - Prob. 9.21RQCh. 9 - Prob. 9.22RQCh. 9 - Prob. 9.23RQCh. 9 - Prob. 9.24RQCh. 9 - Prob. 9.25RQCh. 9 - Describe the current key trends in data...Ch. 9 - Discuss the benefits of offering data warehousing...Ch. 9 - Prob. 9.28RQCh. 9 - List six typical characteristics of reconciled...Ch. 9 - Prob. 9.30RQCh. 9 - Prob. 9.31RQCh. 9 - Prob. 9.32RQCh. 9 - Prob. 9.33RQCh. 9 - Describe some field-level and record-level data...Ch. 9 - Prob. 9.35PAECh. 9 - Prob. 9.36PAECh. 9 - Prob. 9.37PAECh. 9 - Prob. 9.38PAECh. 9 - You are to construct a star schema for Simplified...Ch. 9 - Simplified Automobile Insurance Company would like...Ch. 9 - Prob. 9.41PAECh. 9 - Prob. 9.42PAECh. 9 - Prob. 9.43PAECh. 9 - Prob. 9.45PAECh. 9 - Prob. 9.46PAECh. 9 - Prob. 9.47PAECh. 9 - Prob. 9.48PAECh. 9 - Prob. 9.49PAECh. 9 - Prob. 9.50PAECh. 9 - Prob. 9.51PAECh. 9 - Prob. 9.52PAECh. 9 - Prob. 9.53PAECh. 9 - Prob. 9.54PAE
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