Check whether the sample prove a violation of the guideline that the average patient should pay no more than $250 out-of-pocket.

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Answer 1

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Chapter 9, Problem 92CE

a.

To determine

Check whether the sample prove a violation of the guideline that the average patient should pay no more than $250 out-of-pocket.

b.

To determine

Check whether the decision is close or not.

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A classification study involving several classifiers was carried out. After training and the usual validation step, the following table shows results for classifiers tried. In below, classifiers are identified as M1, M2 and so on. Sensitivity Specificity M1 0.82 0.82 M2 0.92 0.72 M3 0.72 0.92 M4 0.46 0.47 M5 0.03 0.16 M6 0.13 0.02 M7 0.33 0.64 M8 0.72 0.24 M9 0.47 0.82 M10 0.06 0.84 The following list has statements about the classifiers. In the list, there is a single incorrect statement. Please identify the incorrect statement. Hint 1: recall that a classifier dominates another if both performance measures are better. Hint 2: to help you visualize and compare classifiers, you may want to plot the classifier data in a ROC graph (which will not be submitted). Select one: Qa. O b. Oc. d. By swapping zeroes and ones, M5 can be worsened M8 does not dominate M9 M1 dominates all of M4, M5 and M6 M1 is a good classifier ? e. By swapping zeroes and ones, the performance of M4 does not change…

Consider the following training data, shown below before centering. XY 1 0 1 1 1 1 1 1 00 1 1 1 0 0 1 1 1 0 1 1 This data set will be analysed after centering all columns (not scaling). In what follows, the centered data columns are referred to as X and Y. Using these centered columns, we have the following quantities: XTX = 24/11 = 2.1818; XTY = 13/11 = and YTY = 24/11 = 2.1818. Ridge regression Q1 For 2 = R AR = 1.1818 0.56, compute and write in the provided space the ridge estimate ẞ (0.56). Use decimal numbers, not fractions. Q2 Using the ridge estimate ẞ (0.56) you just computed, determine the percentage of shrinkage achieved with respect to the squared L2 norm. That is, compute the shrinkage using || (0.56)||||||with the OLS estimate. In the provided space, write the shrinkage as percentage between 0 and 100 with decimal values. Lasso AR Q3 The following are several expressions for the lasso estimate: (2) = 0.5833 * (1 - 0.84622); L L (a) = 0.5833 * (1 -0.78572); (A) = 0.5417 *…

Calculate the 95% confidence intervals for the proportion of children surviving, and the proportion of non-crew adult passengers surviving. We want to use the given data to make inferences about the general population of all large boat crashes, so the data set should be treated as a random sample for this purpose. Part 2 The 95% confidence interval for survival rate amongst non-crew adults runs from enter your response here% to enter your response here%. (Round to one decimal place as needed. Use ascending order.) Part 3 The 95% confidence interval for survival rate amongst children runs from enter your response here% to enter your response here%. (Round to one decimal place as needed. Use ascending order.) Part 4 Test the alternative hypothesis that the proportion of children surviving does not equal 35%, and next, test the alternative hypothesis that the proportion of non-crew adult passengers surviving does not equal 35%. Again, the data set should…

Answer 2

Question

Chapter 9, Problem 92CE

a.

To determine

Check whether the sample prove a violation of the guideline that the average patient should pay no more than $250 out-of-pocket.

b.

To determine

Check whether the decision is close or not.

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Answer 3

Question

Chapter 9, Problem 92CE

a.

To determine

Check whether the sample prove a violation of the guideline that the average patient should pay no more than $250 out-of-pocket.

b.

To determine

Check whether the decision is close or not.

Expert Solution & Answer

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Answer 4

Question

Chapter 9, Problem 92CE

a.

To determine

Check whether the sample prove a violation of the guideline that the average patient should pay no more than $250 out-of-pocket.

b.

To determine

Check whether the decision is close or not.

Expert Solution & Answer

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Answer 5

Chapter 9, Problem 92CE

a.

To determine

Check whether the sample prove a violation of the guideline that the average patient should pay no more than $250 out-of-pocket.

b.

To determine

Check whether the decision is close or not.

Answer 6

Chapter 9, Problem 92CE

a.

To determine

Check whether the sample prove a violation of the guideline that the average patient should pay no more than $250 out-of-pocket.

Answer 7

Chapter 9, Problem 92CE

a.

To determine

Check whether the sample prove a violation of the guideline that the average patient should pay no more than $250 out-of-pocket.

Answer 8

b.

To determine

Check whether the decision is close or not.

Answer 9

b.

To determine

Check whether the decision is close or not.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 9.2 - If you repealed a hypothesis test 1,000 times (in...Ch. 9.2 - Define Type I and Type II errors for each...Ch. 9.2 - A firm decides to test its employees for illegal...Ch. 9.2 - A hotel installs smoke detectors with adjustable...Ch. 9.2 - What is the consequence of a false negative in an...Ch. 9.2 - Prob. 6SE Ch. 9.3 - A manufacturer claims that its compact fluorescent...Ch. 9.3 - Prob. 8SE Ch. 9.3 - Prob. 9SE Ch. 9.3 - The average age of a part-time seasonal employee...

Check whether the sample prove a violation of the guideline that the average patient should pay no more than $250 out-of-pocket.

Solution Summary: The author explains how the sample does not prove a violation of the guideline that the average patient should pay no more than 250 out-of-pocket.

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Check whether the sample prove a violation of the guideline that the average patient should pay no more than $250 out-of-pocket.

Check whether the decision is close or not.

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Chapter 9 Solutions