Materials for Civil and Construction Engineers (4th Edition)
Materials for Civil and Construction Engineers (4th Edition)
4th Edition
ISBN: 9780134320533
Author: Michael S. Mamlouk, John P. Zaniewski
Publisher: PEARSON
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Chapter 9, Problem 9.1QP
To determine

Write the difference between tar and asphalt cement.

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Explanation of Solution

Difference between tar and asphalt cement as in Table (1):

Asphalt cementTar
Asphalt occurs in natural form or by means of a by-product of petroleum refinery. It is sticky, adhesive, elastic, and easily able to stretch flex and bend without breaking.Tar cannot occur in natural form; it is obtained as a by-product when manufacturing water-gas and coke.
Asphalt is more weather resistant.Tar is more temperature susceptible, usually used to coat aggregates that are more water resistant.
Hot mix paving asphalt creates odor that can be strong and persistent.Tar has an aromatic odor.
Asphalt molecules tend to be aliphatic (referred as a straight chain).Tar tends to be aromatic (referred as cyclic or ring).
Asphalt fume causes health hazards such as skin rash, fatigue, headache, and also skin cancer.Fumes from the heated tar cause health hazards to human beings such as severe eye and skin irritation.

Uses:

They are largely used for pavement construction and maintenance.

It is used as glue with aggregate particles to create the asphalt concrete.

Uses:

They are broadly used in road works because it is superior and also used for preserving timber.

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Question 6: Chlorine is widely used to purify municipal water supplies and to treat swimming pool waters. Suppose that the volume of a particular sample of Cl₂ gas is 8.70 L at 895 torr and 24°C. (a) How many grams of Cl₂ are in the sample? ⚫ Atomic mass of CI = 35.453 g/mol • Molar mass of Cl₂ = 2 x 35.453 = 70.906 g/mol Solution: Use the Ideal Gas Law: Step 1: Convert Given Values • Pressure: P = 895 torr → atm PV= = nRT 1 P = 895 × = 1.1789 atm 760 • Temperature: Convert to Kelvin: T24273.15 = 297.15 K • Gas constant: R = 0.0821 L atm/mol. K Volume: V = 8.70 L Step 2: Solve for n . PV n = RT n = (1.1789)(8.70) (0.0821)(297.15) 10.25 n = = 0.420 mol 24.405 Step 3: Calculate Mass of Cl₂ Final Answer: 29.78 g of Cl₂. mass nx M mass= (0.420)(70.906) mass= 29.78 g
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1. Design a PVC sanitary sewer collection system for the Village of Waffle (Figure P-17-24 B, shown below) by preparing a sewer design table similar to that shown in Example 19-2 and a profile drawing similar to Figure 19-13b B. You only need to show the calculations for the pipes running along Bacon Road and Eggs Road, starting at point F and ending at Point B in the figure below. Your design should comply with the requirements specified in Chapter 30 of the 10 States Standards for Wastewater. Use the following assumptions: 0 о о Average daily flow rate is the same as average daily water demand, 9.2 m³/hr Peaking factor for peak dry weather flow is 6.2 Peak wet weather flow is equal to the peak dry weather flow plus an assumption for infiltration and inflow at 40 L/d-mm-km of pipe DODO on Ro 450 m 28 m D. 150 m Apartments D 400 m D 200 m B 250 m 0 Dogs Road ROOD625 m -120 m Syrup River 120 m 100-Year flood Point Elevation Tank 137.0 m A 130.0 m B 122.0 m C 122.3 m D 122.6 m A D 300 m…
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