EBK PRINCIPLES OF FOUNDATION ENGINEERIN
8th Edition
ISBN: 9780100547056
Author: Das
Publisher: YUZU
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Textbook Question
Chapter 9, Problem 9.12P
Solve Problem 12.13 using Eqs. (12.59) and (12.60).
12.13 A concrete pile 16 in. × 16 in. in cross section is shown in Figure P12.13. Calculate the ultimate skin friction resistance by using the
- a. α method [use Eq. (12.61) and Table 12.11]
- b. λ method
- c. β method
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11.10 A concrete pile 0.406 m x 0.406 m in cross section is
shown in Figure P11.10. Calculate the ultimate skin friction
resistance by using the
a. a method
b. A method
c. ẞ method
Use =20° for all clays, which are normally consolidated.
6.1 m
12.2 m
0.406 m
Figure P11.10
Groundwater
table
Ysat
Silty clay
18.55 kN/m³
Cu = 35 kN/m²
Silty clay
Ysat
=
19.24 kN/m³
Cu = 75 kN/m²
i need the answer quickly
A 20-m-long concrete pile is shown in Figure P9.1. Estimate the ultimate point load
Q, by
a. Meyerhof's method
b. Vesic's method
c. Coyle and Castello's method
Use m = 600 in Eq. (9.26).
9.1
Concrete pile
460 mm x 460 mm
Loose sand
di = 30°
y = 18.6 kN/m3
20 m
Dense sand
d'2 = 42°
y = 18.5 kN/m3
Figure P9.1
Chapter 9 Solutions
EBK PRINCIPLES OF FOUNDATION ENGINEERIN
Ch. 9 - A 20 m long concrete pile is shown in Figure...Ch. 9 - Refer to the pile shown in Figure P9.1. Estimate...Ch. 9 - Prob. 9.3PCh. 9 - A driven closed-ended pile, circular in cross...Ch. 9 - Prob. 9.5PCh. 9 - Prob. 9.6PCh. 9 - Prob. 9.7PCh. 9 - Prob. 9.8PCh. 9 - Prob. 9.9PCh. 9 - A concrete pile 16 in. 16 in. in cross section is...
Ch. 9 - Prob. 9.11PCh. 9 - Solve Problem 12.13 using Eqs. (12.59) and...Ch. 9 - Prob. 9.13PCh. 9 - Prob. 9.14PCh. 9 - A steel pile (H-section; HP 310 125; see Table...Ch. 9 - A concrete pile is 20 m long and has a cross...Ch. 9 - Prob. 9.17PCh. 9 - Prob. 9.18PCh. 9 - Solve Problem 12.23 using the method of Broms....Ch. 9 - Prob. 9.20PCh. 9 - Solve Problem 12.25 using the modified EN formula....Ch. 9 - Solve Problem 12.25 using the modified Danish...Ch. 9 - Figure 12.49a shows a pile. Let L = 15 m, D (pile...Ch. 9 - Redo Problem 12.30 assuming that the water table...Ch. 9 - Refer to Figure 12.49b. Let L = 18 m, fill = 17...Ch. 9 - A concrete pile measuring 16 in. × 16 in. in cross...Ch. 9 - The plan of a group pile is shown in Figure...Ch. 9 - Prob. 9.28PCh. 9 - The section of a 4 × 4 group pile in a layered...Ch. 9 - Prob. 9.30P
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- Refer to the pile shown in Figure P 9.1. Estimate the side resistance Qs bya. Using Eqs. (9.40) through (9.42). Use K = 1.5 and ẟ' = 0.6 Φ'b. Coyle and Castello’s method [Eq. (9.44)]arrow_forwardA 20-m-long concrete pile is shown in Figure P9.1. Estimate the ultimate point load Qp bya. Meyerhof’s methodb. Vesic’s methodc. Coyle and Castello’s methodUse m = 600 in Eq. (9.26).arrow_forwardPlease answer 11.22arrow_forward
- 7. If a 45 cm diameter pipe pile is driven into clayey soil to a depth of 12 m. (a) what would the allowable load capacity (Q) be? The water table is 2 m below the ground surface and the soil profile consists of two clay layers (refer to the figure below). Use the ß method to calculate skin friction and the R=30° for all clay layers. (b) Explain how you selected FS value you use. 12 m 9m 2 m 45 cm Y = 18.5kN/m²³ C= 30kN/m² Ysat = 19kN/m³ Cu = 30kN/m² Ysat = 20kN/m² S = 60kN/m²arrow_forward7. If a 45 cm diameter pipe pile is driven into clayey soil to a depth of 12 m. (a) what would the allowable load capacity (Q) be? The water table is 2 m below the ground surface and the soil profile consists of two clay layers (refer to the figure below). Use the ß method to calculate skin friction and the R=30° for all clay layers. (b) Explain how you selected FS value you use. 12 m ▶ 9m 2m 45 cm Y = 18.5kN/m³ = 30kN/m² Ysat = 19kN/m³ C₂ = 30kN/m² Ysat = 20kN/m² S = 60kN/m²arrow_forward12.20 A 600 mm diameter and 25 m long driven concrete pile car- ries a column load of 1200 kN. It is estimated that the shaft carries 900 kN and the point carries 300 kN. Determine the settlement of the pile head using the Poulos and Davis method with the following data: E = 25 MN/m², Ep = 30,000 MN/m², and μ = 0.2arrow_forward
- A concrete pile 20 m long having a cross section of 0.46 m × 0.46 m is fully embedded in a saturated clay layer. For the clay, given: Yat = 18 kN/m², = 0, and Cu = 80 kN/m?. Determine the allowable load that the pile can carry (FS = 3). Use %3D the A method to estimate the skin resistance.arrow_forward. 11.10 A concrete pile 16i n angle*16 in. in cross section is shown in Figure P11.10. Calcu late the ultimate skin friction resistance by using the a. a methodist b. A method c. ẞ method med phi_{R}' = 20 deg for all clays, which are normally consolidated.arrow_forwardA driven closed-ended pile, circular in cross section, is shown in Figure P 9.4.Calculate the following.a. The ultimate point load using Meyerhof’s procedure.b. The ultimate point load using Vesic’s procedure. Take Irr = 50.c. An approximate ultimate point load on the basis of parts (a) and (b).d. The ultimate frictional resistance Qs. [Use Eqs. (9.40 (L' ≈ 15 D)) through (9.42), and take K = 1.4 and ẟ' = 0.6 Φ'.]e. The allowable load of the pile (use FS = 4).arrow_forward
- A driven closed-ended pile, circular in cross section, is shown in Figure 1. Calculate the following. a. The ultimate point load using Meyerhof’s procedure. b. The ultimate point load using Vesic’s procedure. Take Irr = 50.arrow_forwardConsider a 15 m long concrete pile with a cross section of 0.45 m x 0.45 m fully embedded in sand.For the sand, unit weight, γ = 17 kN/m3 and soil friction angle, ϕ’ = 35o. Estimate the ultimate point??? with each of the following:1.1 Meyerhof’s method (Ans: 1014 kN)1.2 Vesic’s method (Ans: 1754 kN)1.3 Coyle and Castello’s method (Ans: 2479 kN)arrow_forwardA 20 m long concrete pile is shown in Figure P12.2. Estimate the ultimate point load Qp by a. Meyerhofs method b. Vesics method c. Coyle and Castellos method Use m = 600 in Eq. (12.28).arrow_forward
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