Explanation Calculation: Consider the Sun and Jupiter is two ends of the star-planet system. Refer to equation 9.2 in the textbook. Find the radius of the circular orbit ( r c m ) using the equation. r c m = ∑ m i r i M = m J r J + m S r S m J + m S (1) Here, the mass of the Jupiter is m J orbital radius of the Jupiter is r J , the mass of the Sun is m S , and the orbital radius of the Sun is r S . Consider the center of the Sun as origin. Therefore, the orbital radius of the Sun is zero. r S = 0 . Refer to Appendix E “Astrophysical Data” in the textbook. The mass of the Jupiter is m J = 1.90 × 10 27 kg . The mean distance from the central body of the Jupiter is r J = 779 × 10 6 km . The mass of the sun is m S = 1.99 × 10 30 kg . Refer to Appendix B “The International System of Units (SI)” in the textbook

4th Edition

ISBN: 9780134988559

Author: Wolfson, Richard

Publisher: Pearson Education,

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Chapter 9, Problem 90P

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To find: the radius of the circular orbit the Sun makes about the Sun-Jupiter center of mass.

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Chapter 9, Problem 89P

Chapter 9, Problem 91P

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Chapter 9 Solutions

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Knowledge Booster

the radius of the circular orbit the Sun makes about the Sun-Jupiter center of mass.

Solution Summary: The author calculates the radius of the circular orbit using the equation 9.2 in the book.

To find: the radius of the circular orbit the Sun makes about the Sun-Jupiter center of mass.

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Chapter 9 Solutions