Explanation 1) Concept: Using the law of conservation of momentum, we can find the velocity of block R at 0.800 s after release if the spring gives block L a release speed of 1.20 m/s relative to the floor. From this we can easily find the distance travelled by the block R corresponding to it.Similarly we can find the distance travelled by the block R in 0.800 s after release if the spring gives block L a release speed of 1.20 m/s relative to velocity of R using the concept of relativity. 2) Formulae: i) Momentum of the system before release = Momentum of the system after release. ii) x = v t 3) Given: i) Mass of the block L is, m L = 1.00 k g . ii) Mass of the block R is, m R = 0.500 k g . iii) Speed of the block L relative to the floor is, v L = - 1.20 m / s . iv) Speed of the block L relative to the speed of the block R is, v r = - 1.20 m s . 4) Calculations: a) Total momentum of the system is conserved if no external force acts on it. According to the law of conservation of momentum, Momentum of the system before release = Momentum of the system after release ∴ 0 = m L v L + m R v R 0 = ( 1.00 ) ( - 1.20 ) + ( 0.500 ) ( v R ) v R = 2.40 x R = v R t = 2

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Chapter 9, Problem 83P

To determine

To find:

a) The distance travelled by the block R in 0.800 s after release, if the spring gives block L a release speed of 1.20 m/s relative to the floor.

b) The distance travelled by the block R in 0.800 s after release, if the spring gives block L a release speed of 1.20 m/s relative to velocity of R.

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Chapter 9, Problem 82P

Chapter 9, Problem 84P

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a) The distance travelled by the block R in 0.800 s after release, if the spring gives block L a release speed of 1.20 m/s relative to the floor. b) The distance travelled by the block R in 0.800 s after release, if the spring gives block L a release speed of 1.20 m/s relative to velocity of R.

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