Explanation Stokes’ law gives the resistive force on a very small spherical object falling slowly through a fluid of viscosity η with radius r is F r = 6 π r v η . Now this expression is rearranged for the viscosity of air , if all other values are known. Given info : The viscos force on an oil drop is 3.0 × 10 − 13 N , the speed of oil drop is 4.5 × 10 − 4 m/s , and radius of the oil drop is 2.5 × 10 − 6 m . The formula for the viscosity of air is, η = F r 6 π r v F r is viscos force. r is radius of the oil drop. v is speed of oil drop. Substitute 3.0 × 10 − 13 N for F r , 4.5 × 10 − 4 m/s for v , and 2

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Chapter 9, Problem 75P

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The viscosity of air.

Solution Summary: The author explains how Stokes' law gives the resistive force on a very small spherical object falling slowly through the fluid of viscosity.

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