Aspartame is an artificial sweetener marketed under the name Nutra-Sweet. A partial Lewis structure for aspartame is shown below. Aspartame can be classified as an organic compound (a compound based on carbon atoms). The majority of Lewis structures for simple organic compounds have all atoms with a formal charge of zero. Therefore, add lone pairs and multiple bonds to the structure above to give each atom a formal charge of zero when drawing the Lewis structure. Also note that the six-sided ring is shorthand notation for a benzene ring (—C 6 H 5 ). Benzene is discussed in Section 4-7. Complete the Lewis structure for aspartame. How many C and N atoms exhibit sp 1 hybridization? How many C and O atoms exhibit sp 3 hybridization? How many σ and π bonds are in aspartame?
Aspartame is an artificial sweetener marketed under the name Nutra-Sweet. A partial Lewis structure for aspartame is shown below. Aspartame can be classified as an organic compound (a compound based on carbon atoms). The majority of Lewis structures for simple organic compounds have all atoms with a formal charge of zero. Therefore, add lone pairs and multiple bonds to the structure above to give each atom a formal charge of zero when drawing the Lewis structure. Also note that the six-sided ring is shorthand notation for a benzene ring (—C 6 H 5 ). Benzene is discussed in Section 4-7. Complete the Lewis structure for aspartame. How many C and N atoms exhibit sp 1 hybridization? How many C and O atoms exhibit sp 3 hybridization? How many σ and π bonds are in aspartame?
Solution Summary: The author explains the Lewis structure for aspertame and the hybridization of the carbon nitrogen and oxygen atoms present.
Aspartame is an artificial sweetener marketed under the name Nutra-Sweet. A partial Lewis structure for aspartame is shown below.
Aspartame can be classified as an organic compound (a compound based on carbon atoms). The majority of Lewis structures for simple organic compounds have all atoms with a formal charge of zero. Therefore, add lone pairs and multiple bonds to the structure above to give each atom a formal charge of zero when drawing the Lewis structure. Also note that the six-sided ring is shorthand notation for a benzene ring (—C6H5). Benzene is discussed in Section 4-7. Complete the Lewis structure for aspartame. How many C and N atoms exhibit sp1 hybridization? How many C and O atoms exhibit sp3 hybridization? How many σ and π bonds are in aspartame?
Relative Intensity
Part VI. consider the multi-step reaction below for compounds A, B, and C.
These compounds were subjected to mass spectrometric analysis and
the following spectra for A, B, and C was obtained.
Draw the structure of B and C and match all three compounds
to the correct spectra.
Relative Intensity
Relative Intensity
20
NaоH
0103
Br
(B)
H2504
→ (c)
(A)
100-
MS-NU-0547
80
40
20
31
10
20
100-
MS2016-05353CM
80
60
100
MS-NJ-09-3
80
60
40
20
45
J.L
80
S1
84
M+
absent
राग
135 137
S2
62
164 166
11
S3
25
50
75
100
125
150
175
m/z
Don't used hand raiting and don't used Ai solution
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