(a) Interpretation: For the given situations, it is to be determined that whether both liquid and gas are present (L/G), only gas is present (G), or situation is impossible (I). In flask I, the pressure is 256 mm of Hg. Concept introduction: The vapor pressure of a liquid is pressure exerted by its vapor which are present just above its surface.
(a) Interpretation: For the given situations, it is to be determined that whether both liquid and gas are present (L/G), only gas is present (G), or situation is impossible (I). In flask I, the pressure is 256 mm of Hg. Concept introduction: The vapor pressure of a liquid is pressure exerted by its vapor which are present just above its surface.
Solution Summary: The author explains that the vapor pressure of a liquid is pressure exerted by its liquid which are present just above its surface.
For the given situations, it is to be determined that whether both liquid and gas are present (L/G), only gas is present (G), or situation is impossible (I).
In flask I, the pressure is 256 mm of Hg.
Concept introduction:
The vapor pressure of a liquid is pressure exerted by its vapor which are present just above its surface.
Interpretation Introduction
(b)
Interpretation:
For the given situation, if both liquid and gas are present (L/G), only gas is present (G), and situation is impossible (I) needs to be determined.
In flask II, the pressure is 135 mm of Hg.
Concept introduction:
The vapor pressure of a liquid is pressure exerted by its vapor which are present just above its surface.
Interpretation Introduction
(c)
Interpretation:
For the given situation, if both liquid and gas are present (L/G), only gas is present (G), and situation is impossible (I) needs to be determined.
In flask III, the pressure is 165 mm of Hg at 30°C, if temperature is decreased to20°C, the pressure becomes 159 mm Hg.
Concept introduction:
The vapor pressure of a liquid is pressure exerted by its vapor which are present just above its surface.
Consider a solution of 0.00304 moles of 4-nitrobenzoic acid (pKa = 3.442) dissolved in 25 mL water and titrated with 0.0991 M NaOH. Calculate the pH at the equivalence point
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