ORGANIC CHEMISTRY, WITH SOL. MAN/ STUDY
ORGANIC CHEMISTRY, WITH SOL. MAN/ STUDY
3rd Edition
ISBN: 9781119477617
Author: Klein
Publisher: WILEY
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Chapter 9, Problem 66IP
Interpretation Introduction

Interpretation:

The given set of organic molecules plausible mechanism should be draw identified.

Concept Introduction:

Deuterium Oxide D2O (or) Heavy water: This type of water contains a large than normal amount of the hydrogen isotope deuterium ORGANIC CHEMISTRY, WITH SOL. MAN/ STUDY, Chapter 9, Problem 66IP , rather than the common hydrogen (1H or H) that makes up most of the hydrogen in normal water.     

Tautomerism: The two isomers refer to a chemical equilibrium between a keto (-C=O) form and an enol (-C-OH) . The two types of enol and keto forms are said to be tautomers of each other. Further the intramolecular process of two forms involves the movement of single hydrogen atom shifted of bonding electron, these type isomers (or) called as tautomerism

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5 What would the complete ionic reaction be if aqueous solutions of potassium sulfate and barium acetate were mixed? ed of Select one: O a 2 K SO4 + Ba2 +2 C₂H3O21 K+SO4 + Ba2+ + 2 C2H3O21 K+SO42 + Ba2 +2 C2H3O2 BaSO4 +2 K+ + 2 C2H3O estion Ob. O c. Od. 2 K SO4 +Ba2 +2 C₂H₂O₂ BaSO4 + K+ + 2 C2H3O BaSO4 + K + 2 C2H301 →Ba² +SO42 +2 KC2H3O s page
(28 pts.) 7. Propose a synthesis for each of the following transformations. You must include the reagents and product(s) for each step to receive full credit. The number of steps is provided. (OC 4) 4 steps 4 steps OH b.
LTS Solid: AT=Te-Ti Trial 1 Trial 2 Trial 3 Average ΔΗ Mass water, g 24.096 23.976 23.975 Moles of solid, mol 0.01763 001767 0101781 Temp. change, °C 2.9°C 11700 2.0°C Heat of reaction, J -292.37J -170.473 -193.26J AH, kJ/mole 16.58K 9.647 kJ 10.85 kr 16.58K59.64701 KJ mol 12.35k Minimum AS, J/mol K 41.582 mol-k Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn & Show your calculations for: AH in J and then in kJ/mole for Trial 1: qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J qsin = qrxn = 292.35 292.37J AH in J = 292.375 0.2923kJ 0.01763m01 =1.65×107 AH in kJ/mol = = 16.58K 0.01763mol mol qrx Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con Kelvin.) AS=AHIT (1.65×10(9.64×103) + (1.0 Jimai

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ORGANIC CHEMISTRY, WITH SOL. MAN/ STUDY

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