The diameter of the bubble in arc seconds.

Question

For each problem, use the following values: c = 3x108 m/s mass of the sun = 1.989 x 1030 kg luminosity of the sun = 3.828 x 1026 W 1 AU = 1.496 x 1011 m 1 pc = 3.262 light years = 3.086 x 1016 m 1 year=3.154x107 seconds Critical density of our Universe (expressed as a mass density): Pcrit =8.7 x 10-27 kg m-³ Critical energy density of our Universe: Ecrit = Pcrit c² G=6.674 × 10-11 m³.kg-1.s-2 1 eV = 1.60218 x10-19. Boltzmann constant: kg = 1.381 x 10-23 JK-18.617 × 10-5eV K-1 energy density constant (in Stefan Boltzmann Law): a = 7.566 x 10-16 Jm-3 K-4 -4.7 x 10-³ MeV m-3 K-4 Constant in Wein displacement law: b = 2.898 x 10-3 m K baryon-to-photon ratio, n = 6 x 10-10

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Chapter 9, Problem 5P

To determine

The diameter of the bubble in arc seconds.

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For each problem, use the following values: c = 3x108 m/s mass of the sun = 1.989 x 1030 kg luminosity of the sun = 3.828 x 1026 W 1 AU = 1.496 x 1011 m 1 pc = 3.262 light years = 3.086 x 1016 m 1 year=3.154x107 seconds Critical density of our Universe (expressed as a mass density): Pcrit =8.7 x 10-27 kg m-³ Critical energy density of our Universe: Ecrit = Pcrit c² G=6.674 × 10-11 m³.kg-1.s-2 1 eV = 1.60218 x10-19. Boltzmann constant: kg = 1.381 x 10-23 JK-18.617 × 10-5eV K-1 energy density constant (in Stefan Boltzmann Law): a = 7.566 x 10-16 Jm-3 K-4 -4.7 x 10-³ MeV m-3 K-4 Constant in Wein displacement law: b = 2.898 x 10-3 m K baryon-to-photon ratio, n = 6 x 10-10

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