The arrangement of atoms when volume increases thrice is to determined. Concept Introduction: At constant temperature, when pressure ( P ) is increased on a gas, consequently volume ( V ) of the gas decreases in accordance with Boyleâ€™s law. Mathematically represented as: P ∝ 1 V P 1 V 1 = P 2 V 2 When pressure is increased, the space between the molecules decreases due to which molecules come closer and the number of molecules per unit volume increases. Hence, the density of the gas increases

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Answer 1

Question

Chapter 9, Problem 36QP

Interpretation Introduction

Interpretation:

The arrangement of atoms when volume increases thrice is to determined.

Concept Introduction:

At constant temperature, when pressure (P) is increased on a gas, consequently volume (V) of the gas decreases in accordance with Boyleâ€™s law. Mathematically represented as:

P∝1VP1V1=P2V2

When pressure is increased, the space between the molecules decreases due to which molecules come closer and the number of molecules per unit volume increases. Hence, the density of the gas increases

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Answer 2

Question

Chapter 9, Problem 36QP

Interpretation Introduction

Interpretation:

The arrangement of atoms when volume increases thrice is to determined.

Concept Introduction:

At constant temperature, when pressure (P) is increased on a gas, consequently volume (V) of the gas decreases in accordance with Boyleâ€™s law. Mathematically represented as:

P∝1VP1V1=P2V2

When pressure is increased, the space between the molecules decreases due to which molecules come closer and the number of molecules per unit volume increases. Hence, the density of the gas increases

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 9, Problem 36QP

Interpretation Introduction

Interpretation:

The arrangement of atoms when volume increases thrice is to determined.

Concept Introduction:

At constant temperature, when pressure (P) is increased on a gas, consequently volume (V) of the gas decreases in accordance with Boyleâ€™s law. Mathematically represented as:

P∝1VP1V1=P2V2

When pressure is increased, the space between the molecules decreases due to which molecules come closer and the number of molecules per unit volume increases. Hence, the density of the gas increases

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 9, Problem 36QP

Interpretation Introduction

Interpretation:

The arrangement of atoms when volume increases thrice is to determined.

Concept Introduction:

At constant temperature, when pressure (P) is increased on a gas, consequently volume (V) of the gas decreases in accordance with Boyleâ€™s law. Mathematically represented as:

P∝1VP1V1=P2V2

When pressure is increased, the space between the molecules decreases due to which molecules come closer and the number of molecules per unit volume increases. Hence, the density of the gas increases

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 5

Chapter 9, Problem 36QP

Interpretation Introduction

Interpretation:

The arrangement of atoms when volume increases thrice is to determined.

Concept Introduction:

At constant temperature, when pressure (P) is increased on a gas, consequently volume (V) of the gas decreases in accordance with Boyleâ€™s law. Mathematically represented as:

P∝1VP1V1=P2V2

When pressure is increased, the space between the molecules decreases due to which molecules come closer and the number of molecules per unit volume increases. Hence, the density of the gas increases

Answer 6

Chapter 9, Problem 36QP

Interpretation Introduction

Interpretation:

The arrangement of atoms when volume increases thrice is to determined.

Concept Introduction:

At constant temperature, when pressure (P) is increased on a gas, consequently volume (V) of the gas decreases in accordance with Boyleâ€™s law. Mathematically represented as:

P∝1VP1V1=P2V2

When pressure is increased, the space between the molecules decreases due to which molecules come closer and the number of molecules per unit volume increases. Hence, the density of the gas increases

Answer 7

Chapter 9, Problem 36QP

Interpretation Introduction

Interpretation:

The arrangement of atoms when volume increases thrice is to determined.

Concept Introduction:

At constant temperature, when pressure (P) is increased on a gas, consequently volume (V) of the gas decreases in accordance with Boyleâ€™s law. Mathematically represented as:

P∝1VP1V1=P2V2

When pressure is increased, the space between the molecules decreases due to which molecules come closer and the number of molecules per unit volume increases. Hence, the density of the gas increases

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 9 - Prob. 1QC Ch. 9 - Prob. 2QC Ch. 9 - Prob. 3QC Ch. 9 - Prob. 4QC Ch. 9 - Prob. 5QC Ch. 9 - Prob. 1PP Ch. 9 - Prob. 2PP Ch. 9 - What pressure is needed to compress 455 mL of...Ch. 9 - Prob. 4PP Ch. 9 - Prob. 5PP

Solution Summary: The author explains the arrangement of atoms when volume increases thrice. When the piston is moved upwards, the particles of gas go apart and intermolecular space increases.

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