INTOR TO CHEMISTRY LLF
INTOR TO CHEMISTRY LLF
5th Edition
ISBN: 9781264501731
Author: BAUER
Publisher: MCG
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Chapter 9, Problem 163QP

(a)

Interpretation Introduction

Interpretation:

The gas which occupies the greatest volume at STP is to be determined.

(a)

Expert Solution
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Explanation of Solution

The number of moles of a gas n is equal to the ratio of mass of the gas m to the molar mass MM of the gas.

n=mMM …… (1)

STP is the standard temperature and pressure. At STP, the volume of a gas occupied by 1 mol of gas at 1 atm and 273.15 K is 22.414 L . So, the volume occupied by a gas at STP can be determined by its molar volume.

46.2 g N2

The number of moles of N2 gas can be determined by using equation (1). The molar mass of N2 gas is:

N2=2×14 g mol1=28 g mol1

Substitute m as 46.2 g and MM as 28 g mol1 in equation (1):

n=46.2 g28 g mol1=1.65 mol

The volume occupied by 1 mol of N2 gas at STP is:

1mol=22.414 L

The volume occupied by 1.65 mol of N2 gas at STP is:

1.65 mol=22.414 L1mol×1.65 mol=37 L

Therefore, option (a) is the incorrect option.

(b)

Interpretation Introduction

Interpretation:

The gas which occupies the greatest volume at STP is to be determined.

(b)

Expert Solution
Check Mark

Explanation of Solution

24.3 g H2

The number of moles of H2 gas can be determined by using equation (1). The molar mass of H2 gas is:

H2=2×1 g mol1=2 g mol1

Substitute m as 24.3 g and MM as 2 g mol1 in equation (1):

n=24.3 g2 g mol1=12.15 mol

The volume occupied by 1 mol of H2 gas at STP is:

1mol=22.414 L

The volume occupied by 12.15 mol of H2 gas at STP is:

12.15 mol=22.414 L1mol×12.15 mol=272.33 L

Therefore, H2 gas is the gas which occupies the greatest volume at STP. Therefore, option (b) is the correct option.

(c)

Interpretation Introduction

Interpretation:

The gas which occupies the greatest volume at STP is to be determined.

(c)

Expert Solution
Check Mark

Explanation of Solution

54.1 g CO2

The number of moles of CO2 gas can be determined by using equation (1). The molar mass of CO2 gas is:

CO2=12 g mol1+2×16 g mol1=44 g mol1

Substitute m as 54.1 g and MM as 44 g mol1 in equation (1):

n=54.1 g44 g mol1=1.23 mol

The volume occupied by 1 mol of CO2 gas at STP is:

1mol=22.414 L

The volume occupied by 1.23 mol of CO2 gas at STP is:

1.23 mol=22.414 L1mol×1.23 mol=27.6 L

Therefore, option (c) is the incorrect option.

(d)

Interpretation Introduction

Interpretation:

The gas which occupies the greatest volume at STP is to be determined.

(d)

Expert Solution
Check Mark

Explanation of Solution

39.4 g Ar

The number of moles of Ar gas can be determined by using equation (1). The molar mass of Ar gas is:

Ar=40 g mol1

Substitute m as 39.4 g and MM as 40 g mol1 in equation (1):

n=39.4 g40 g mol1=0.985 mol

The volume occupied by 1 mol of Ar gas at STP is:

1mol=22.414 L

The volume occupied by 0.985 mol of Ar gas at STP is:

0.985 mol=22.414 L1mol×0.985 mol=22.1 L

Therefore, option (d) is the incorrect option.

(e)

Interpretation Introduction

Interpretation:

The gas which occupies the greatest volume at STP is to be determined.

(e)

Expert Solution
Check Mark

Explanation of Solution

21.5 g NH3

The number of moles of NH3 gas can be determined by using equation (1). The molar mass of NH3 gas is:

NH3=14 g mol1+3×1 g mol1=17 g mol1

Substitute m as 21.5 g and MM as 17 g mol1 in equation (1):

n=21.5 g17 g mol1=1.3 mol

The volume occupied by 1 mol of Ar gas at STP is:

1mol=22.414 L

The volume occupied by 1.3 mol of Ar gas at STP is:

1.3 mol=22.414 L1mol×1.3 mol=28.24 L

Therefore, option (e) is the incorrect option.

Arrange the volumes in the increasing order as follows:

272.33 L>37.0 L>28.24 L>27.6 L>22.1 LB>A>E>C>D

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INTOR TO CHEMISTRY LLF

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