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Concept explainers
Interpretation:
The series of equations for the preparation of each of the given compound from the designated starting material using suitable organic or inorganic reagents is to be written.
Concept introduction:
The conjugate base of alkyne acts as a good nucleophile. On reaction with primary
In hydration of alkynes, a molecule of water gets added to a molecule of alkyne.Hydrogen atom gets attached to the less substituted triple bonded carbon atom, and hydroxyl groupgetsbonded to the more substituted triple bonded carbon atom and forms a
Geminal and vicinal dihalides, on reaction with a strong base, undergo double dehydrohalogenation and form alkynes.
On halogenation, alkynes form vicinal dihalides and, on reaction with hydrogen halides, they form geminal dihalides in two steps.
Primary alcohol can be converted to primary alkyl bromide by reaction with sodium bromide in acidic condition.
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Answer to Problem 36P
Solution:
a)
b)
c)
d)
e)
f)
g)
h)
Explanation of Solution
a)
The
The synthesis of
b)
The
The synthesis of
c)
The
The synthesis of
d)
Acetylene on treatment with sodium amide, gives sodium salt of acetylene. The sodium salt of acetylene on treatment with ethyl bromide gives
The synthesis of
e)
Acetylene on treatment with sodium amide, gives sodium salt of acetylene. In presence of organoboron,
The synthesis of
f)
In presence of organoboron,
The synthesis of
g)
Cyclopentadecene on halogenation with
The synthesis of
h)
In presence of base sodium amide, the given alkyne gives sodium salt of alkyne. The sodium salt of alkyne on treatment with bromomethane adds one methyl group to alkyne, which on partial hydrogenation with Lindlar catalyst gives required cis alkene.
The synthetic route is as follows:
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Chapter 9 Solutions
ORGANIC CHEMISTRY (LOOSELEAF)-PACKAGE
- Please answer the questions in the photos and please revise any wrong answers. Thank youarrow_forward(Please be sure that 7 carbons are available in the structure )Based on the 1H NMR, 13C NMR, DEPT 135 NMR and DEPT 90 NMR, provide a reasoning step and arrive at the final structure of an unknown organic compound containing 7 carbons. Dept 135 shows peak to be positive at 128.62 and 13.63 Dept 135 shows peak to be negative at 130.28, 64.32, 30.62 and 19.10.arrow_forward-lease help me answer the questions in the photo.arrow_forward
- For the reaction below, the concentrations at equilibrium are [SO₂] = 0.50 M, [0] = 0.45 M, and [SO3] = 1.7 M. What is the value of the equilibrium constant, K? 2SO2(g) + O2(g) 2SO3(g) Report your answer using two significant figures. Provide your answer below:arrow_forwardI need help with this question. Step by step solution, please!arrow_forwardZn(OH)2(s) Zn(OH)+ Ksp = 3 X 10-16 B₁ = 1 x 104 Zn(OH)2(aq) B₂ = 2 x 1010 Zn(OH)3 ẞ3-8 x 1013 Zn(OH) B4-3 x 1015arrow_forward
- Help me understand this by showing step by step solution.arrow_forwardscratch paper, and the integrated rate table provided in class. our scratch work for this test. Content attribution 3/40 FEEDBACK QUESTION 3 - 4 POINTS Complete the equation that relates the rate of consumption of H+ and the rate of formation of Br2 for the given reaction. 5Br (aq) + BrO3 (aq) + 6H (aq) →3Br2(aq) + 3H2O(l) • Your answers should be whole numbers or fractions without any decimal places. Provide your answer below: Search 尚 5 fn 40 * 00 99+ 2 9 144 a [arrow_forward(a) Write down the structure of EDTA molecule and show the complex structure with Pb2+ . (b) When do you need to perform back titration? (c) Ni2+ can be analyzed by a back titration using standard Zn2+ at pH 5.5 with xylenol orange indicator. A solution containing 25.00 mL of Ni2+ in dilute HCl is treated with 25.00 mL of 0.05283 M Na2EDTA. The solution is neutralized with NaOH, and the pH is adjusted to 5.5 with acetate buffer. The solution turns yellow when a few drops of indicator are added. Titration with 0.02299 M Zn2+ requires 17.61 mL to reach the red end point. What is the molarity of Ni2+ in the unknown?arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
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