ORGANIC CHEMISTRY (LOOSELEAF)-PACKAGE
ORGANIC CHEMISTRY (LOOSELEAF)-PACKAGE
10th Edition
ISBN: 9781260008562
Author: Carey
Publisher: MCG
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Chapter 9, Problem 27P
Interpretation Introduction

Interpretation:

The principal product in each of the given reactions is to be predicted.

Concept introduction:

The conjugate base of alkyne acts as a good nucleophile. On reaction with primary alkyl halide, it undergoes substitution reaction. The order of better leaving group of halogen in a nucleophilic substitution reaction is I>Br>Cl>F.

Alkynes, on hydrogenation with catalyst Lindlar palladium, undergo syn addition and yield cis alkene.

Alkynes, on hydration, undergo addition of a molecule of water. The hydrogen atom is bonded to less substituted triple bonded carbon, and the hydroxyl groupis bonded to more substituted triple bonded carbon atom and forms a ketone through enol formation.

Germinal and vicinal dihalides, on reaction with a strong base, undergo double dehydrohalogenation and form alkynes.

Ozonolysis of alkynes involves the cleavage of triple bond and formation of carboxylic acids as products. An acyclic alkyne forms two carboxylic acids whereas a cyclic alkyne forms a single product with two carboxylic acid groups.

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Please help me to figure this out. I got 24 is that correct? Please step by step help.
The initial rates method can be used to determine the rate law for a reaction. using the data for the reaction below, what is the rate law for reaction? A+B-C - ALA] At (mot Trial [A] (mol) (MD 2 1 0.075 [B]( 0.075 mo LS 01350 2 0.075 0.090 0.1944 3 0.090 0.075 0.1350 Report value of k with two significant Figure
Compare trials 1 and 2 where [B] is constant. The rate law can be written as: rate = k[A][B]". rate2 0.090 = 9. rate1 0.010 [A]m 6.0m = 3m [A] m 2.0m

Chapter 9 Solutions

ORGANIC CHEMISTRY (LOOSELEAF)-PACKAGE

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