The Essentials of Computer Organization and Architecture
4th Edition
ISBN: 9781284045611
Author: Linda Null, Julia Lobur
Publisher: Jones & Bartlett Learning
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Chapter 9, Problem 2E
Program Plan Intro
Reduced Instruction Set Computer (RISC):
- In this computer, the instruction set architecture (ISA) allows lesser number of cycles per instruction (CPI) when compared to complex instruction set computer (CISC).
- As this contains a simple and general set of instructions, it is also called as “Relegate interesting stuff to the Compiler”.
- It also has another trait and that is the load/store architecture, in which the memory is accessed through specific instructions rather than as a part of most instructions.
Complex Instruction Set Computer (CISC):
- Complex instruction set computing (CISC) uses the variable length instructions and accesses memory directly and efficiently.
- As the length of the instructions increases, the processing time also increases.
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Students have asked these similar questions
1. Create a Book record that implements the Comparable interface, comparing the
Book objects by year
- title: String
>
- author: String
- year: int
Book
+ compareTo(other Book: Book): int
+ toString(): String
Submit your source code on Canvas (Copy
your code to text box or upload.java file)
>
Comparable
2. Create a main method in Book record.
1) In the main method, create an array of 2 objects of Book with your choice of
title, author, and year.
2) Sort the array by year
3) Print the object. Override the toString in Book to match the example output:
@Javadoc Declaration Console X Properties
Book [Java Application] /Users/kuan/.p2/pool/plugins/org.eclipse.justj.openjdk.hotspo
[Book: year=1901, Book: year=2010]
Q5-The efficiency of a 200 KVA, single phase transformer is 98% when operating at full load 0.8
lagging p.f. the iron losses in the transformer is 2000 watt. Calculate the i) Full load copper losses ii)
half load copper losses and efficiency at half load. Ans: 1265.306 watt, 97.186%
2. Consider the following pseudocode for partition:
function partition (A,L,R)
pivotkey = A [R]
t = L
for i
L to R-1 inclusive:
if A[i] A[i]
t = t + 1
end if
end for
A [t] A[R]
return t
end function
Suppose we call partition (A,0,5) on A=[10,1,9,2,8,5]. Show the state of the list at the
indicated instances.
Initial A
After i=0 ends
After 1 ends
After i 2 ends
After i = 3 ends
After i = 4 ends
After final swap
10 19 285
[12 pts]
Chapter 9 Solutions
The Essentials of Computer Organization and Architecture
Ch. 9 - Prob. 1RETCCh. 9 - Prob. 2RETCCh. 9 - Prob. 3RETCCh. 9 - Prob. 4RETCCh. 9 - Prob. 5RETCCh. 9 - Prob. 6RETCCh. 9 - Prob. 7RETCCh. 9 - Prob. 8RETCCh. 9 - Prob. 9RETCCh. 9 - Prob. 10RETC
Ch. 9 - Prob. 11RETCCh. 9 - Prob. 12RETCCh. 9 - Prob. 13RETCCh. 9 - Prob. 14RETCCh. 9 - Prob. 15RETCCh. 9 - Prob. 16RETCCh. 9 - Prob. 17RETCCh. 9 - Prob. 18RETCCh. 9 - Prob. 19RETCCh. 9 - Prob. 20RETCCh. 9 - Prob. 21RETCCh. 9 - Prob. 22RETCCh. 9 - Prob. 23RETCCh. 9 - Prob. 24RETCCh. 9 - Prob. 25RETCCh. 9 - Prob. 26RETCCh. 9 - Prob. 1ECh. 9 - Prob. 2ECh. 9 - Prob. 3ECh. 9 - Prob. 4ECh. 9 - Prob. 5ECh. 9 - Prob. 6ECh. 9 - Prob. 7ECh. 9 - Prob. 8ECh. 9 - Prob. 9ECh. 9 - Prob. 11ECh. 9 - Prob. 12ECh. 9 - Prob. 13ECh. 9 - Prob. 14ECh. 9 - Prob. 15ECh. 9 - Prob. 16ECh. 9 - Prob. 17ECh. 9 - Prob. 18ECh. 9 - Prob. 19ECh. 9 - Prob. 20ECh. 9 - Prob. 21ECh. 9 - Prob. 22ECh. 9 - Prob. 23ECh. 9 - Prob. 24ECh. 9 - Prob. 25ECh. 9 - Prob. 26ECh. 9 - Prob. 27ECh. 9 - Prob. 28ECh. 9 - Prob. 29ECh. 9 - Prob. 31ECh. 9 - Prob. 32ECh. 9 - Prob. 33E
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