Chapter 9, Problem 25P

To determine

The normal force exerted by the floor on each foot.

Answer to Problem 25P

Solution:

  $102.14\text{ N}$

Explanation of Solution

Given:

Mass of the mas, $m=68\text{ kg}$

Formula used:

For equilibrium:

  ${\displaystyle \sum F=ma=0}$

Here, m is the mass and a is the acceleration .

Calculation:

  $\begin{array}{l}{\displaystyle \sum F=0}\\ 2F_h+2F_F-mg=0\\ 2(231.06)+2F_F-68(9.8)=0\\ 462.12+2F_F-666.4=0\\ 2F_F-204.28=0\\ F_F=102.14\text{N}\end{array}$

Conclusion:

Thus, the normal force exerted on each foot is $102.14\text{N}$ .