PRIN.OF OPERATIONS MANAGEMENT-MYOMLAB
PRIN.OF OPERATIONS MANAGEMENT-MYOMLAB
11th Edition
ISBN: 9780135226742
Author: HEIZER
Publisher: PEARSON
Question
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Chapter 9, Problem 20P

a)

Summary Introduction

To draw: The precedence diagram.

a)

Expert Solution
Check Mark

Answer to Problem 20P

PRIN.OF OPERATIONS MANAGEMENT-MYOMLAB, Chapter 9, Problem 20P , additional homework tip  1

Explanation of Solution

Given information:

Task Time (minutes) Immediate predecessors
A 3 -
B 6 -
C 7 A
D 5 A, B
E 2 B
F 4 C
G 5 F
H 7 D, E
I 1 H
J 6 E
K 4 G, I, J
Total 50  
  • Number of hours / day is 24
  • Output is 96 instruments / day.

Precedence diagram:

PRIN.OF OPERATIONS MANAGEMENT-MYOMLAB, Chapter 9, Problem 20P , additional homework tip  2

b)

Summary Introduction

To determine: The cycle time.

Introduction:

Cycle time:

Cycle time is the total time taken to complete an unit of work from the beginning of the process to the end of the process.

b)

Expert Solution
Check Mark

Answer to Problem 20P

The  cycle time is 15 minutes / unit.

Explanation of Solution

Formula to calculate cycle time:

Cycle time=Number of hours per dayDaily production× Number of minutes / hour

Calculation of cycle time:

Cycle time=2496×60=1,44096=15 minutes / unit

The  cycle time is 15 minutes / unit.

c)

Summary Introduction

To determine: The production rate.

c)

Expert Solution
Check Mark

Answer to Problem 20P

The  production rate is 144 units / day.

Explanation of Solution

Given information:

Cycle time = 10 minutes

Formula to calculate production rate:

Cycle time=Number of hours per dayCycle time× Number of minutes / hour

Calculation of cycle time:

Cycle time=2410×60=1,44010=144 units / day

The  production rate is 144 units / day.

d)

Summary Introduction

To determine: The theoretical minimum number of workstations.

d)

Expert Solution
Check Mark

Answer to Problem 20P

The theoretical minimum number of workstations is 5 workstations.

Explanation of Solution

Given information:

Cycle time = 10 minutes

Formula to calculate theoretical minimum number of workstations:

Workstations=Total task timeCycle time

Calculation of theoretical minimum number of workstations:

Workstations=5010=5 workstations

The theoretical minimum number of workstations is 5 workstations.

e)

Summary Introduction

To determine: The efficiency.

Introduction:

Efficiency:

Efficiency is the measure of  what is actually produced as opposed to what can be theoretically produced with the same amount of resources.

e)

Expert Solution
Check Mark

Answer to Problem 20P

The efficiency is 83.3%.

Explanation of Solution

Given information:

Cycle time = 10 minutes

Number of workstations = 6

Formula to calculate efficiency:

Efficiency=Total task timeNumber of workstations×Cycle time×100

Calculation of efficiency:

Efficiency=506×10×100=50060=83.3%

The efficiency is 83.3%.

f)

Summary Introduction

To determine: The total idle time per cycle.

f)

Expert Solution
Check Mark

Answer to Problem 20P

The  idle time is 10 minutes / cycle.

Explanation of Solution

Given information:

Number of workstations = 6

Cycle time = 10

Calculation of total idle time per cycle:

Total idle time=(Number of workstations×Cycle time)-Total task time=(6×10)-50=60-50=10 minutes / cycle

The  total idle time is 10 minutes / cycle.

g)

Summary Introduction

To assign: The different tasks to different workstations and identify the efficiency.

g)

Expert Solution
Check Mark

Explanation of Solution

Assignment of different tasks to different workstations:

Workstation Elligible tasks Selected tasks Task time (minutes) Available cycle time (minutes)
1 10
A, B A 3 7
B B 6 1
1 (Idle time)
2 10
C, D, E C 7 3
3 (Idle time)
3 10
D, E, F D 5 5
E, F E 2 3
3 (Idle time)
4 10
F, G, H, I F 4 6
G, H, I G 5 1
1 (Idle time)
5 10
J, H, I, K H 7 3
H, I, K I 1 2
2 (Idle time)
6 10
K, J J 6 4
K K 4 0
Workstation Task assigned Idle time
1 A, B 1
2 C, D 3
3 D, E 3
4 F, G 1
5 H, I 2
6 J, K 0
Total 10

Efficiency:

Formula to calculate efficiency:

Efficiency=Total task timeNumber of workstations×Cycle time×100

Calculation of efficiency:

Efficiency=506×10×100=50060=83.3%

The efficiency is 83.3%.

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Dr. Lori Baker, operations manager at Nesa Electronics, prides herself on excellent assembly-line balancing. She has been told that the firm needs to complete 96 instruments per 24-hour day. The assembly-line activities are:                                                                                                               a) Draw the precedence diagram.b) Tf the daily (24-hour) production rate is 96 units, what is the highest allowable cycle time?c) If the cycle time after allowances is given as 10 minutes, what is the daily (24-hour) production rate?d) With a 10-minute cycle time, what is the theoretical minimum number of stations with which the line can be balanced?e) With a I 0-minute cycle time and six workstations, what is the efficiency?f) What is the total idle time per cycle with a I 0-minute cycle time and six workstations?g) What is the best workstation assignment you can make without exceeding a I 0-minute cycle time, and what is its efficiency?
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