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Concept explainers
Chlamydomonas, a eukaryoric green alga, may be sensitive to the antibiotic erythromycin, which inhibits protein synthesis in bacteria. There are two mating types in this alga, mt+ and mt–. If an mt+ cell sensitive to the antibiotic is crossed with an mt– cell that is resistant, all progeny cells are sensitive. The reciprocal cross (mt+ resistant and mt– sensitive) yields all resistant progeny cells. Assuming that the mutation for resistance is in the chloroplast DNA, what can you conclude from the results of these crosses?
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To determine: The conclusion that can be drawn from the results of the given crosses.
Introduction: Chlamydomonas is a eukaryotic green alga and shows two mating types mt+ and mt-. The cross between mt+ cell (sensitive to antibiotic) and mt- cell (resistant to antibiotic) produces sensitive progeny cells.
Explanation of Solution
The following conclusions can be drawn from the results of the given crosses:
- The mt+ strain of Chlamydomonas is the donor of the chloroplast DNA. This is because the inheritance of resistance or sensitivity to the antibiotic relies on the status of mt+ gene.
- In Chlamydomonas, the chloroplasts obtain their features from mt+, whereas mitochondria obtain their features from the mt- strain.
Thus, mt+ strain is the donor of chloroplast DNA and the chloroplasts gain their characteristics from mt+. The mitochondria obtain their features from mt-.
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Chapter 9 Solutions
Concepts of Genetics (11th Edition)
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