BIG JAVA: LATE OBJECTS
2nd Edition
ISBN: 9781119626220
Author: Horstmann
Publisher: WILEY
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Expert Solution & Answer
Chapter 9, Problem 16RE
Explanation of Solution
Computation of (int)(a-b):
- It is given that the value assigned to a is “0.6” and the value assigned to b is “0.3”.
- Whenever there is a type conversion from a wide data to a narrow data, the loss of precision takes place.
- Since, int is narrower than the double, whenever a double is type casted to an int, then the loss of precision takes place...
Explanation of Solution
Computation of (int)(b-a):
- It is given that the value assigned to a is “0.6” and the value assigned to b is “0.3”.
- Whenever there is a type conversion from a wide data to a narrow data, the loss of precision takes place.
- Since, int is narrower than the double, whenever a double is type casted to an int, then the loss of precision takes place...
Explanation of Solution
Result of Double.compare(a, b):
- The method Double.compare(a, b) compares two test values for the order in which they must come.
- If the variable on the left side is less than the right side, then “-1” is returned.
- Otherwise, if the variable on the left side is greater than the right side, then “1” is returned...
Explanation of Solution
Result of Double.compare(b, a):
- The method Double.compare(b, a) compares two test values for the order in which they must come.
- If the variable on the left side is less than the right side, then “-1” is returned.
- Otherwise, if the variable on the left side is greater than the right side, then “1” is returned...
Expert Solution & Answer
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Students have asked these similar questions
Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head =
{
NULL) return 0;
first;
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head = head->next;
return 0;
void test ll_has_cycle () {
int i;
node nodes [6];
for (i = 0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value = i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next
nodes [4] .next
&nodes [4];
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
how to read log logs
Discrete Mathematics for Computer Engineering
Chapter 9 Solutions
BIG JAVA: LATE OBJECTS
Ch. 9.1 - Prob. 1SCCh. 9.1 - Prob. 2SCCh. 9.1 - Prob. 3SCCh. 9.1 - Prob. 4SCCh. 9.1 - Prob. 5SCCh. 9.2 - Prob. 6SCCh. 9.2 - Prob. 7SCCh. 9.2 - Prob. 8SCCh. 9.2 - Prob. 9SCCh. 9.2 - Prob. 10SC
Ch. 9.3 - Prob. 11SCCh. 9.3 - Prob. 12SCCh. 9.3 - Prob. 13SCCh. 9.3 - Prob. 14SCCh. 9.3 - Prob. 15SCCh. 9.4 - Prob. 16SCCh. 9.4 - Prob. 17SCCh. 9.4 - Prob. 18SCCh. 9.4 - Prob. 19SCCh. 9.4 - Prob. 20SCCh. 9.5 - Prob. 21SCCh. 9.5 - Prob. 22SCCh. 9.5 - Prob. 23SCCh. 9.5 - Prob. 24SCCh. 9.5 - Prob. 25SCCh. 9.6 - Prob. 26SCCh. 9.6 - Prob. 27SCCh. 9.6 - Prob. 28SCCh. 9.6 - Prob. 29SCCh. 9.6 - Prob. 30SCCh. 9.6 - Prob. 31SCCh. 9 - Prob. 1RECh. 9 - Prob. 2RECh. 9 - Prob. 3RECh. 9 - Prob. 4RECh. 9 - Prob. 5RECh. 9 - Prob. 6RECh. 9 - Prob. 7RECh. 9 - Prob. 8RECh. 9 - Prob. 9RECh. 9 - Prob. 10RECh. 9 - Prob. 11RECh. 9 - Prob. 12RECh. 9 - Prob. 13RECh. 9 - Prob. 14RECh. 9 - Prob. 15RECh. 9 - Prob. 16RECh. 9 - Prob. 1PECh. 9 - Prob. 2PECh. 9 - Prob. 3PECh. 9 - Prob. 4PECh. 9 - Prob. 7PECh. 9 - Prob. 8PECh. 9 - Prob. 9PECh. 9 - Prob. 10PECh. 9 - Prob. 11PECh. 9 - Prob. 12PECh. 9 - Prob. 13PECh. 9 - Prob. 14PECh. 9 - Prob. 15PECh. 9 - Prob. 16PECh. 9 - Prob. 18PECh. 9 - Prob. 19PECh. 9 - Prob. 20PECh. 9 - Prob. 21PECh. 9 - Prob. 22PECh. 9 - Prob. 23PECh. 9 - Prob. 1PPCh. 9 - Prob. 2PPCh. 9 - Prob. 3PPCh. 9 - Prob. 4PPCh. 9 - Prob. 5PPCh. 9 - Prob. 6PPCh. 9 - Prob. 7PPCh. 9 - Prob. 8PPCh. 9 - Prob. 9PPCh. 9 - Prob. 10PPCh. 9 - Prob. 11PPCh. 9 - Prob. 12PPCh. 9 - Prob. 13PPCh. 9 - Prob. 14PPCh. 9 - Prob. 15PPCh. 9 - Prob. 16PPCh. 9 - Prob. 17PPCh. 9 - Prob. 18PPCh. 9 - Prob. 19PPCh. 9 - Prob. 20PPCh. 9 - Prob. 21PPCh. 9 - Prob. 22PPCh. 9 - Prob. 23PP
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