Introduction To Chemistry 5th Edition
Introduction To Chemistry 5th Edition
5th Edition
ISBN: 9781260162097
Author: BAUER
Publisher: MCG
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Chapter 9, Problem 161QP

(a)

Interpretation Introduction

Interpretation:

The gas which has the greatest density is to be identified.

(a)

Expert Solution
Check Mark

Explanation of Solution

The ideal gas equation states that pressure P and volume of a gas V is directly proportional to number of moles n and temperature T of the gas.

PV=nRT …… (1)

Here, R is the universal gas constant having value 0.08206 L atm mol1K1 .

Density ρ of a gas is equal to the ratio of mass m of the gas to the volume V of the gas.

ρ=mV …… (2)

The number of moles n is equal to the ratio of mass m of the gas to the molar mass MM of the gas.

n=mMM …… (3)

The gas is kept in 2.50 L container with pressure of 1.12 atm and temperature 25°C . Convert temperature units from degree Celsius to kelvin as follows:

TK=T°C+273.15

Convert temperature 25°C units from degree Celsius to kelvin as follows:

T=25+273.15=298.15 K

Substitute P as 1.12 atm , V as 2.50 L , R as 0.08206 L atm mol1 K1 , and T as 298.15 K in equation (1):

1.12 atm×2.50 L=n×0.08206 L atm mol1 K1×298.15 Kn=1.12 atm×2.50 L0.08206 L atm mol1 K1×298.15 K=0.114 mol

The molar mass of N2 gas is as follows:

N2=2×14 g mol1=28 g mol1

Substitute n as 0.114 mol and MM as 28 g mol1 in equation (3):

0.114 mol=m28 g mol1m=3.192 g

Substitute m as 3.192 g and V as 2.50 L in equation (2):

ρ=3.192g2.50 L=1.278 g L1

(b)

Interpretation Introduction

Interpretation:

The gas which has the greatest density is to be identified.

(b)

Expert Solution
Check Mark

Explanation of Solution

The molar mass of O2 gas is as follows:

O2=2×16 g mol1=32 g mol1

Substitute n as 0.114 mol and MM as 32 g mol1 in equation (3):

0.114 mol=m32 g mol1m=3.648 g

Substitute m as 3.648 g and V as 2.50 L in equation (2):

ρ=3.648 g2.50 L=1.46 g L1

(c)

Interpretation Introduction

Interpretation:

The gas which has the greatest density is to be identified.

(c)

Expert Solution
Check Mark

Explanation of Solution

The molar mass of CO2 gas is as follows:

CO2=12 g mol1+2×16 g mol1=44 g mol1

Substitute n as 0.114 mol and MM as 44 g mol1 in equation (3):

0.114 mol=m44 g mol1m=5.016 g

Substitute m as 5.016 g and V as 2.50 L in equation (2):

ρ=5.016 g2.50 L=2.0064 g L1

(d)

Interpretation Introduction

Interpretation:

The gas which has the greatest density is to be identified.

(d)

Expert Solution
Check Mark

Explanation of Solution

The molar mass of He gas is as follows:

He=4 g mol1

Substitute n as 0.114 mol and MM as 4 g mol1 in equation (3):

0.114 mol=m4 g mol1m=0.456 g

Substitute m as 0.456 g and V as 2.50 L in equation (2):

ρ=0.456 g2.50 L=0.227 g L1

(e)

Interpretation Introduction

Interpretation:

The gas which has the greatest density is to be identified.

(e)

Expert Solution
Check Mark

Explanation of Solution

The molar mass of SO2 gas is as follows:

SO2=32 g mol1+2×16 g mol1=64 g mol1

Substitute n as 0.114 mol and MM as 64 g mol1 in equation (3):

0.114 mol=m64 g mol1m=7.296 g

Substitute m as 7.296 g and V as 2.50 L in equation (2):

ρ=7.296 g2.50 L=2.918 g L1

Therefore, sulfur dioxide is the gas having the highest density.

The arrangement in the increasing order of the densities of gases are:

SO2>CO2>O2>N2>He .

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Chapter 9 Solutions

Introduction To Chemistry 5th Edition

Ch. 9 - Prob. 6PPCh. 9 - Prob. 7PPCh. 9 - Prob. 8PPCh. 9 - Prob. 9PPCh. 9 - Prob. 10PPCh. 9 - Prob. 11PPCh. 9 - Prob. 12PPCh. 9 - Prob. 13PPCh. 9 - Prob. 14PPCh. 9 - Prob. 15PPCh. 9 - Prob. 16PPCh. 9 - Prob. 17PPCh. 9 - Prob. 18PPCh. 9 - Prob. 1QPCh. 9 - Prob. 2QPCh. 9 - Prob. 3QPCh. 9 - Prob. 4QPCh. 9 - A series of organic compounds called the alkanes...Ch. 9 - Prob. 6QPCh. 9 - Prob. 7QPCh. 9 - Prob. 8QPCh. 9 - Prob. 9QPCh. 9 - Prob. 10QPCh. 9 - Prob. 11QPCh. 9 - Prob. 12QPCh. 9 - Prob. 13QPCh. 9 - Prob. 14QPCh. 9 - Prob. 15QPCh. 9 - Prob. 16QPCh. 9 - Prob. 17QPCh. 9 - Prob. 18QPCh. 9 - Prob. 19QPCh. 9 - Prob. 20QPCh. 9 - Prob. 21QPCh. 9 - Prob. 22QPCh. 9 - Prob. 23QPCh. 9 - Prob. 24QPCh. 9 - Prob. 25QPCh. 9 - Prob. 26QPCh. 9 - Prob. 27QPCh. 9 - Prob. 28QPCh. 9 - Prob. 29QPCh. 9 - Prob. 30QPCh. 9 - Prob. 31QPCh. 9 - Prob. 32QPCh. 9 - Prob. 33QPCh. 9 - Prob. 34QPCh. 9 - Prob. 35QPCh. 9 - Prob. 36QPCh. 9 - Prob. 37QPCh. 9 - Prob. 38QPCh. 9 - Prob. 39QPCh. 9 - Prob. 40QPCh. 9 - Prob. 41QPCh. 9 - Prob. 42QPCh. 9 - Prob. 43QPCh. 9 - Prob. 44QPCh. 9 - Prob. 45QPCh. 9 - Prob. 46QPCh. 9 - Prob. 47QPCh. 9 - Prob. 48QPCh. 9 - Prob. 49QPCh. 9 - Prob. 50QPCh. 9 - Prob. 51QPCh. 9 - Prob. 52QPCh. 9 - Prob. 53QPCh. 9 - Prob. 54QPCh. 9 - Prob. 55QPCh. 9 - Prob. 56QPCh. 9 - Prob. 57QPCh. 9 - Prob. 58QPCh. 9 - Prob. 59QPCh. 9 - Prob. 60QPCh. 9 - Prob. 61QPCh. 9 - Prob. 62QPCh. 9 - Prob. 63QPCh. 9 - Prob. 64QPCh. 9 - Prob. 65QPCh. 9 - Prob. 66QPCh. 9 - Prob. 67QPCh. 9 - Prob. 68QPCh. 9 - Prob. 69QPCh. 9 - Prob. 70QPCh. 9 - Prob. 71QPCh. 9 - Prob. 72QPCh. 9 - Prob. 73QPCh. 9 - Prob. 74QPCh. 9 - Prob. 75QPCh. 9 - Prob. 76QPCh. 9 - Prob. 77QPCh. 9 - Prob. 78QPCh. 9 - Prob. 79QPCh. 9 - Prob. 80QPCh. 9 - Prob. 81QPCh. 9 - Prob. 82QPCh. 9 - Prob. 83QPCh. 9 - Prob. 84QPCh. 9 - Prob. 85QPCh. 9 - Prob. 86QPCh. 9 - Prob. 87QPCh. 9 - Prob. 88QPCh. 9 - Prob. 89QPCh. 9 - Prob. 90QPCh. 9 - Prob. 91QPCh. 9 - Prob. 92QPCh. 9 - Prob. 93QPCh. 9 - Prob. 94QPCh. 9 - Prob. 95QPCh. 9 - Prob. 96QPCh. 9 - Prob. 97QPCh. 9 - Prob. 98QPCh. 9 - Prob. 99QPCh. 9 - Prob. 100QPCh. 9 - Prob. 101QPCh. 9 - Prob. 102QPCh. 9 - Prob. 103QPCh. 9 - Prob. 104QPCh. 9 - Prob. 105QPCh. 9 - Prob. 106QPCh. 9 - Prob. 107QPCh. 9 - Prob. 108QPCh. 9 - Prob. 109QPCh. 9 - Prob. 110QPCh. 9 - Prob. 111QPCh. 9 - Prob. 112QPCh. 9 - Prob. 113QPCh. 9 - Prob. 114QPCh. 9 - Prob. 115QPCh. 9 - Prob. 116QPCh. 9 - Prob. 117QPCh. 9 - Prob. 118QPCh. 9 - Prob. 119QPCh. 9 - Prob. 120QPCh. 9 - Prob. 121QPCh. 9 - Prob. 122QPCh. 9 - Prob. 123QPCh. 9 - Prob. 124QPCh. 9 - Prob. 125QPCh. 9 - Prob. 126QPCh. 9 - Prob. 127QPCh. 9 - Prob. 128QPCh. 9 - Prob. 129QPCh. 9 - Prob. 130QPCh. 9 - Prob. 131QPCh. 9 - Prob. 132QPCh. 9 - Prob. 133QPCh. 9 - Prob. 134QPCh. 9 - Prob. 135QPCh. 9 - Prob. 136QPCh. 9 - Prob. 137QPCh. 9 - Prob. 138QPCh. 9 - Prob. 139QPCh. 9 - Prob. 140QPCh. 9 - Prob. 141QPCh. 9 - Prob. 142QPCh. 9 - Prob. 143QPCh. 9 - Prob. 144QPCh. 9 - Prob. 145QPCh. 9 - Prob. 146QPCh. 9 - Prob. 147QPCh. 9 - Prob. 148QPCh. 9 - Prob. 149QPCh. 9 - Prob. 150QPCh. 9 - Prob. 151QPCh. 9 - Prob. 152QPCh. 9 - Prob. 153QPCh. 9 - Prob. 154QPCh. 9 - Prob. 155QPCh. 9 - Prob. 156QPCh. 9 - Prob. 157QPCh. 9 - Prob. 158QPCh. 9 - Prob. 159QPCh. 9 - Prob. 160QPCh. 9 - Prob. 161QPCh. 9 - Prob. 162QPCh. 9 - Prob. 163QPCh. 9 - Prob. 164QPCh. 9 - Prob. 165QPCh. 9 - Butane burns with oxygen according to the...Ch. 9 - Prob. 167QP
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