COMPTIA A+ GUIDE TO IT TECH SUPPORT
10th Edition
ISBN: 9780357466810
Author: ANDREWS
Publisher: CENGAGE L
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Chapter 9, Problem 10TC
Explanation of Solution
Given:
A car with a media system that can sync with an iPhone.
To find: The app that can be downloaded to sync with the media...
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Briefly define and discuss the following classes of problems: P, NP, NP-Complete, co-NP, NC, P-Complete.
A3Q3.c - You are to write a C program that implements the following disk scheduling
algorithms:
a. FCFS [10 marks]
b. SCAN [10 marks]
c. C-SCAN [10 marks]
d. SSTF [10 marks]
e. LOOK [10 marks]
f. C-LOOK [10 marks]
•
Your program will service a disk with 300 cylinders numbered 0 to 299.
•
•
•
•
The program will service the requests (a list of 20 cylinder numbers) given in the file
request.bin.
This file contains (4 byte) integer values representing requests ranging from 0-299.
Your program will take the initial position of the disk head as the first command line
argument and the direction of the head as the second command line argument.
It will then output the requests in the order in which they are serviced, and the total
amount of head movements required by each algorithm.
In particular, your program needs to do the following:
Your program should take two command line arguments
a) First command line argument - initial position of the disk head (an integer value)
b) Second command line…
2. The memory management has contiguous memory allocation, dynamic partitions,
and paging. Compare the internal fragmentation and external fragmentation for
these three approaches. [2 marks]
3. Suppose we have Logical address space = 24 = 16 (m = 4), Page size=2² =4 (n = 2),
Physical address space = 26 = 64 (r = 6). Answer the following questions: [4 marks]
1) Total # of pages ?
2) Total # of frames ?
3) Number of bits to represent logical address?
4) Number of bits to represent offset ?
5) Number of bits to represent physical address?
6) Number of bits to represent a page number?
7) Number of bits to represent a frame number /
4. What is translation look-aside buffers (TLBS)? Why we need them to implement the
page table? [2 marks]
5. Why we need shared pages for multiple processes? Give one example to show the
benefits. [2 marks]
6. How to implement the virtual memory by using page out and page in? Explain with
an example. [2 marks]
7. We have a reference string of referenced page…
Chapter 9 Solutions
COMPTIA A+ GUIDE TO IT TECH SUPPORT
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- make corrections of this program based on the errors shown. this is CIS 227 .arrow_forwardCreate 6 users: Don, Liz, Shamir, Jose, Kate, and Sal. Create 2 groups: marketing and research. Add Shamir, Jose, and Kate to the marketing group. Add Don, Liz, and Sal to the research group. Create a shared directory for each group. Create two files to put into each directory: spreadsheetJanuary.txt meetingNotes.txt Assign access permissions to the directories: Groups should have Read+Write access Leave owner permissions as they are “Everyone else” should not have any access Submit for grade: Screenshot of /etc/passwd contents showing your new users Screenshot of /etc/group contents showing new groups with their members Screenshot of shared directories you created with files and permissionsarrow_forward⚫ your circuit diagrams for your basic bricks, such as AND, OR, XOR gates and 1 bit multiplexers, ⚫ your circuit diagrams for your extended full adder, designed in Section 1 and ⚫ your circuit diagrams for your 8-bit arithmetical-logical unit, designed in Section 2. 1 An Extended Full Adder In this Section, we are going to design an extended full adder circuit (EFA). That EFA takes 6 one bit inputs: aj, bj, Cin, Tin, t₁ and to. Depending on the four possible combinations of values on t₁ and to, the EFA produces 3 one bit outputs: sj, Cout and rout. The EFA can be specified in principle by a truth table with 26 = 64 entries and 3 outputs. However, as the EFA ignores certain inputs in certain cases, it is easier to work with the following overview specification, depending only on t₁ and to in the first place: t₁ to Description 00 Output Relationship Ignored Inputs Addition Mode 2 Coutsjaj + bj + Cin, Tout= 0 Tin 0 1 Shift Left Mode Sj = Cin, Cout=bj, rout = 0 rin, aj 10 1 1 Shift Right…arrow_forward
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