An Introduction to Physical Science
14th Edition
ISBN: 9781305079137
Author: James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher: Cengage Learning
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Chapter 9, Problem 10E
To determine
Energy in eV of the photon absorbed when an electron jumps up from the
n = 1 n = 4
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Chapter 9 Solutions
An Introduction to Physical Science
Ch. 9.1 - Prob. 1PQCh. 9.1 - Prob. 2PQCh. 9.2 - Prob. 1PQCh. 9.2 - Prob. 2PQCh. 9.2 - Prob. 9.1CECh. 9.3 - Prob. 1PQCh. 9.3 - When does a hydrogen atom emit or absorb radiant...Ch. 9.3 - Prob. 9.2CECh. 9.3 - Prob. 9.3CECh. 9.3 - Prob. 9.4CE
Ch. 9.4 - Prob. 1PQCh. 9.4 - Prob. 2PQCh. 9.5 - Prob. 1PQCh. 9.5 - Prob. 2PQCh. 9.6 - Prob. 1PQCh. 9.6 - Prob. 2PQCh. 9.6 - Prob. 9.5CECh. 9.7 - Prob. 1PQCh. 9.7 - Prob. 2PQCh. 9 - Prob. AMCh. 9 - Prob. BMCh. 9 - Prob. CMCh. 9 - Prob. DMCh. 9 - Prob. EMCh. 9 - Prob. FMCh. 9 - Prob. GMCh. 9 - Prob. HMCh. 9 - Prob. IMCh. 9 - Prob. JMCh. 9 - Prob. KMCh. 9 - Prob. LMCh. 9 - Prob. MMCh. 9 - Prob. NMCh. 9 - Prob. OMCh. 9 - Prob. PMCh. 9 - Prob. QMCh. 9 - Prob. 1MCCh. 9 - Prob. 2MCCh. 9 - Prob. 3MCCh. 9 - Prob. 4MCCh. 9 - Prob. 5MCCh. 9 - Prob. 6MCCh. 9 - Prob. 7MCCh. 9 - Prob. 8MCCh. 9 - Prob. 9MCCh. 9 - Prob. 10MCCh. 9 - Prob. 11MCCh. 9 - Prob. 12MCCh. 9 - Prob. 13MCCh. 9 - Prob. 14MCCh. 9 - Prob. 1FIBCh. 9 - Prob. 2FIBCh. 9 - Prob. 3FIBCh. 9 - Prob. 4FIBCh. 9 - Prob. 5FIBCh. 9 - Prob. 6FIBCh. 9 - Prob. 7FIBCh. 9 - Prob. 8FIBCh. 9 - Prob. 9FIBCh. 9 - Prob. 10FIBCh. 9 - Prob. 11FIBCh. 9 - Prob. 12FIBCh. 9 - Prob. 1SACh. 9 - Prob. 2SACh. 9 - Prob. 3SACh. 9 - Prob. 4SACh. 9 - Prob. 5SACh. 9 - Prob. 6SACh. 9 - Prob. 7SACh. 9 - Prob. 8SACh. 9 - Prob. 9SACh. 9 - Prob. 10SACh. 9 - Prob. 11SACh. 9 - Prob. 12SACh. 9 - Prob. 13SACh. 9 - Prob. 14SACh. 9 - Prob. 15SACh. 9 - Prob. 16SACh. 9 - Prob. 17SACh. 9 - Prob. 18SACh. 9 - Prob. 19SACh. 9 - Prob. 20SACh. 9 - Prob. 21SACh. 9 - Prob. 22SACh. 9 - Prob. 23SACh. 9 - Prob. 24SACh. 9 - Prob. 25SACh. 9 - Prob. 26SACh. 9 - Prob. 27SACh. 9 - Prob. 28SACh. 9 - Prob. 29SACh. 9 - Prob. 30SACh. 9 - Prob. 31SACh. 9 - Prob. 32SACh. 9 - Prob. 33SACh. 9 - Prob. 34SACh. 9 - Visualize the connection for the descriptions of...Ch. 9 - Prob. 1AYKCh. 9 - Prob. 2AYKCh. 9 - Prob. 3AYKCh. 9 - Prob. 4AYKCh. 9 - Prob. 5AYKCh. 9 - Prob. 1ECh. 9 - Prob. 2ECh. 9 - Prob. 3ECh. 9 - Prob. 4ECh. 9 - Prob. 5ECh. 9 - Prob. 6ECh. 9 - Prob. 7ECh. 9 - Prob. 8ECh. 9 - Prob. 9ECh. 9 - Prob. 10ECh. 9 - Prob. 11ECh. 9 - Prob. 12E
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- Use the table to determine the energy in eV of the photon absorbed when an electron jumps up from the n = 1 orbit to the n = 3 orbit of a hydrogen atom. Allowed Values of the Hydrogen Electron's Radius and Energy for Low Values of n n rn En 1 0.053 nm −13.60 eV 2 0.212 nm −3.40 eV 3 0.477 nm −1.51 eV 4 0.848 nm −0.85 eVarrow_forwardThe light observed that is emitted by a hydrogen atom is explained by a simple model of its structure with one proton in its nucleus and an electron bound to it, but only with internal energies of the atom satisfying EH=−RH/n2EH=−RH/n2 where RHRH is the Rydberg constant and nn is an integer such as 1, 2, 3 ... and so on. When a hydrogen atom in an excited state emits light, the photon carries away energy and the atom goes into a lower energy state. Be careful about units. The Rydberg constant in eV is 13.605693009 eV That would be multiplied by the charge on the electron 1.602× 10-19 C to give 2.18× 10-18 J A photon with this energy would have a frequency f such that E=hf. Its wavelength would be λ = c/f = hc/E. Sometimes it is handy to measure the Rydberg constant in units of 1/length for this reason. You may see it given as 109737 cm-1 if you search the web, so be aware that's not joules. The following questions are intended to help you understand the connection between…arrow_forwardA visible (violet) emission spectral line for chromium (Cr) occurs at wavelength λ = 425.435 nm. A) What is the frequency (ν) of this light?(Give correct units and answer to six significant figures.) B) What is the magnitude of the energy change associated with the emission of one mole of photons of light with this wavelength?arrow_forward
- Consider the electron of a Li2+ ion that undergoes a transition from a higher energy state n to its adjacent lower energy state n – 1 (e.g. n = 2→1, 3→2, 4→3, etc) and emits a photon. Suppose the emitted photon is used to strike the surface of potassium, which has a threshold frequency of 5.464 × 10^14 s–1.a) Whatisthemaximuminitialquantumnumber,n, that is required in order to emit a photon with high enough energy to generate a photocurrent from the metal surface?b) Usingthenvaluesolvedinpart(a), calculate the maximum speed of the photoelectron from potassium. If you couldn’t solve for n in part (a), use n = 3.arrow_forwardA ruby laser emits an intense pulse of light that lasts a mere 10 ns . The light has a wavelength of 690 nm , and each pulse has an energy of 400 mJ . How many photons are emitted in each pulse? What is the rate of photon emission, in photons per second, during the 10 nsns that the laser is "on"?arrow_forwardQuestion 9. While most transition metals have work functions corresponding to photon frequencies that are larger (higher) than visible light, alkali and alkaline earth metals have low-energy work functions. For example, calcium has a work function of o = 4.3419×10-19 J. (a) What is the initial state n, for the hydrogen emission lines at visible wavelengths (i.e., those with n = 2) for the lowest-energy photon that would eject an electron from calcium? %3! (b) If the colors of the visible hydrogen emission lines (n; = 3 to n = 6) are red, green, blue and %3D violet, which colors are capable of ejecting the electrons from calcium? (c) The energy of the emitted photon you identified in part (a), is not identical to the workfunction of calcium. Therefore, the electron is ejected from the metal surface with some kinetic energy (i.e., energy is conserved in the photoelectric effect process). What would the velocity of the electron ejected from calcium (in meters per second)?arrow_forward
- A photon with a wavelength of 410 nm has energy Ephoton = 3.0 eV. Do you expect to see a spectral line with λ = 410 nm in the emission spectrum of the atom represented by this energy-level diagram? If so, what transition or transitions will emit it? Do you expect to see a spectral line with λ = 410 nm in the absorption spectrum? If so, what transition or transitions will absorb it?arrow_forwardCopper has a density of 8.9 g/cm3 and a gram-atomic mass of 63.56. The total atomic attenuation coefficient of copper is 8.8 × 10−24 cm2/atom for 500-keV photons. What thickness (in centimeters) of copper is required to attenuate 500-keV photons to half of the original number?arrow_forwardChapter 39, Problem 052 A hydrogen atom is excited from its ground state to the state with n = 4. (a) How much energy must be absorbed by the atom? Consider the photon energies that can be emitted by the atom as it de-excites to the ground state in the several possible ways. (b) How many different energies are possible; what are the (c) highest, (d) second highest, (e) third highest, (f) lowest, (g) second lowest, and (h) third lowest energies? (a) Number Units (b) Number Units (c) Number Units (d) Number Units (e) Number Units (f) Number Units (g) Number Units (h) Number Unitsarrow_forward
- 2. a) Problem 8.3 of Textbook: Calculate the frequency of the hydrogen transition n = 101 → n = 100. b) A light photon emitted from a higher energy level ofn = 3 to a lower energy level of n = 2 in hydrogen has a wavelength of 1 = 656.3 nm. Compute the atom distribution ratio N3/N2 at the equilibrium when temperatures are T = 102K.arrow_forwardUse the table to determine the energy in eV of the photon emitted when an electron jumps down from the n = 2 orbit to the n = 1 orbit of a hydrogen atom. Allowed Values of the Hydrogen Electron's Radius and Energy for Low Values of n n rn En 1 0.053 nm −13.60 eV 2 0.212 nm −3.40 eV 3 0.477 nm −1.51 eV 4 0.848 nm −0.85 eV eVarrow_forwardAn electron with a speed of 1.6×106m/s collides with an atom of element X . Shortly afterward, the atom emits a 1240 nm photon. What was the electron's speed after the collision? Assume that, because the atom is so much more massive than the electron, the recoil of the atom is negligible. Hint: The energy of the photon is not the energy transferred to the atom in the collision.arrow_forward
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