Explanation Given: The given matrix A is [ − 2 3 10 4 − 2 2 ] and the matrix B is [ 1 1 − 5 2 3 2 ] . Approach: The method to find the determinant of square matrices of dimension n × n by using the graphing calculator TI-83 is as follows, Press the button 2 n d x - 1 in the graphing device to enter the matrix. Select the option E D I T and change the order of the matrix. Enter the entries of the matrix. Quit the screen. Again press the button 2 n d x - 1 and select the option NAMES Press enter to select matrix A . Again press the button 2 n d x - 1 and select the option NAMES Press enter to select matrix B . Press enter to multiply the matrix. Calculation: Consider the given matrix, A = [ − 2 3 10 4 − 2 2 ] , B = [ 1 1 − 5 2 3 2 ] Take the graphing calculator TI-83 in performing condition, press the button 2 n d x - 1 in the graphing device to enter the matrix. Select the option E D I T and change the order of the matrix then enter the entries of the given matrix as shown in the below,

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ISBN: 9781337271073

Author: Ron Larson

Publisher: Cengage Learning

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‘Matrices’ is the plural form of the word matrix, and it is basically a spreadsheet in the form of a box. In mathematics, various functions can be carried out with matrices. Generally, a matrix comes in the shape of a square or rectangle. The elements ar…

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Chapter 8.CR, Problem 54CR

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The possibility of finding the value of AB, where A=[−23104−22] and B=[11−5232] by using the graphing utility.

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The possibility of finding the value of A B , where A = [ − 2 3 10 4 − 2 2 ] and B = [ 1 1 − 5 2 3 2 ] by using the graphing utility.

Solution Summary: The author explains how to determine the value of AB by using the graphing utility.

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The possibility of finding the value of AB, where A=[−23104−22] and B=[11−5232] by using the graphing utility.

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