THERMODYNAMICS (LL)-W/ACCESS >CUSTOM<
9th Edition
ISBN: 9781266657610
Author: CENGEL
Publisher: MCG CUSTOM
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Chapter 8.8, Problem 123RP
(a)
To determine
The rate of heat transfer to the steel rods in the oven.
(b)
To determine
The rate of exergy destruction associated with the process.
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Please do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful!
Please do not copy other's work,i will be very very grateful!!
Answer by selecting the correct options from the following multichoice selection.
ப
4m
B
A
C
D
3m
3 m
Figure Q17
FL
12 kN
E
16 KN
A. We should resolve forces in the horizontal direction to easily identify the internal force DF.
B. The solution to the problem is found to be -16 kN (C).
C. We should resolve forces in the vertical direction to first identify the internal force DF.
D. We should use Method of Joints at node F to find the internal force in member DF.
E. We should Method of Sections by cutting through members DF, DE and CE.
F. The starting point to solve this problem is to find all reactions at nodes A and B as they will be required for DF calculations.
G. The solution to the problem is found to be 16 kN (T).
H. The most appropriate method to find DF use is Method of Joints.
I. The most appropriate method to use is Method of Sections.
J. A good starting point to solve this problem is to find the horizontal reaction at node B but this is not required to the internal force
H
2 kN
K
2 kN
M
N
www
RAY
RAX
A
G
B
C
D
E
F
3 m
↑
RGY
4m
Fill in the multiple blanks.
Figure Q19
Finding the vertical reactions is the starting point which can be done by taking moments at A and G but since this is symmetrical loading case the vertical reactions can simply be calculated by halving the total loading 4 kN.
Ideally, we can solve the problem using the Method of
cutting through the members JK, DJ and
It would be sensible to select the left-hand side of the diagram as there are less full members and only one force from the reaction at node A.
This will expose the internal forces which can be labelled with the names of the members themselves.
Since we are required to find JK, examining the framework shows it is not a straight-forward matter, and we will require finding all three unknown internal forces.
The easiest internal force to find is
Next, we can take moments at node
, as we can resolve forces in the vertical direction.
in order to find the internal force JK and find…
Chapter 8 Solutions
THERMODYNAMICS (LL)-W/ACCESS >CUSTOM<
Ch. 8.8 - What final state will maximize the work output of...Ch. 8.8 - Is the exergy of a system different in different...Ch. 8.8 - Under what conditions does the reversible work...Ch. 8.8 - How does useful work differ from actual work? For...Ch. 8.8 - How does reversible work differ from useful work?Ch. 8.8 - Is a process during which no entropy is generated...Ch. 8.8 - Consider an environment of zero absolute pressure...Ch. 8.8 - It is well known that the actual work between the...Ch. 8.8 - Consider two geothermal wells whose energy...Ch. 8.8 - Consider two systems that are at the same pressure...
Ch. 8.8 - Prob. 11PCh. 8.8 - Does a power plant that has a higher thermal...Ch. 8.8 - Prob. 13PCh. 8.8 - Saturated steam is generated in a boiler by...Ch. 8.8 - One method of meeting the extra electric power...Ch. 8.8 - A heat engine that receives heat from a furnace at...Ch. 8.8 - Consider a thermal energy reservoir at 1500 K that...Ch. 8.8 - A heat engine receives heat from a source at 1100...Ch. 8.8 - A heat engine that rejects waste heat to a sink at...Ch. 8.8 - A geothermal power plant uses geothermal liquid...Ch. 8.8 - A house that is losing heat at a rate of 35,000...Ch. 8.8 - A freezer is maintained at 20F by removing heat...Ch. 8.8 - Prob. 24PCh. 8.8 - Prob. 25PCh. 8.8 - Prob. 26PCh. 8.8 - Can a system have a higher second-law efficiency...Ch. 8.8 - A mass of 8 kg of helium undergoes a process from...Ch. 8.8 - Which is a more valuable resource for work...Ch. 8.8 - Which has the capability to produce the most work...Ch. 8.8 - The radiator of a steam heating system has a...Ch. 8.8 - A well-insulated rigid tank contains 6 lbm of a...Ch. 8.8 - A pistoncylinder device contains 8 kg of...Ch. 8.8 - Prob. 35PCh. 8.8 - Prob. 36PCh. 8.8 - Prob. 37PCh. 8.8 - A pistoncylinder device initially contains 2 L of...Ch. 8.8 - A 0.8-m3 insulated rigid tank contains 1.54 kg of...Ch. 8.8 - An insulated pistoncylinder device initially...Ch. 8.8 - Prob. 41PCh. 8.8 - An insulated rigid tank is divided into two equal...Ch. 8.8 - A 50-kg iron block and a 20-kg copper block, both...Ch. 8.8 - Prob. 45PCh. 8.8 - Prob. 46PCh. 8.8 - Prob. 47PCh. 8.8 - A pistoncylinder device initially contains 1.4 kg...Ch. 8.8 - Prob. 49PCh. 8.8 - Prob. 50PCh. 8.8 - Prob. 51PCh. 8.8 - Air enters a nozzle steadily at 200 kPa and 65C...Ch. 8.8 - Prob. 54PCh. 8.8 - Prob. 55PCh. 8.8 - Argon gas enters an adiabatic compressor at 120...Ch. 8.8 - Prob. 57PCh. 8.8 - Prob. 58PCh. 8.8 - The adiabatic compressor of a refrigeration system...Ch. 8.8 - Refrigerant-134a at 140 kPa and 10C is compressed...Ch. 8.8 - Air enters a compressor at ambient conditions of...Ch. 8.8 - Combustion gases enter a gas turbine at 900C, 800...Ch. 8.8 - Steam enters a turbine at 9 MPa, 600C, and 60 m/s...Ch. 8.8 - Refrigerant-134a is condensed in a refrigeration...Ch. 8.8 - Prob. 66PCh. 8.8 - Refrigerant-22 absorbs heat from a cooled space at...Ch. 8.8 - Prob. 68PCh. 8.8 - Prob. 69PCh. 8.8 - Air enters a compressor at ambient conditions of...Ch. 8.8 - Hot combustion gases enter the nozzle of a...Ch. 8.8 - Prob. 72PCh. 8.8 - A 0.6-m3 rigid tank is filled with saturated...Ch. 8.8 - Prob. 74PCh. 8.8 - Prob. 75PCh. 8.8 - An insulated vertical pistoncylinder device...Ch. 8.8 - Liquid water at 200 kPa and 15C is heated in a...Ch. 8.8 - Prob. 78PCh. 8.8 - Prob. 79PCh. 8.8 - A well-insulated shell-and-tube heat exchanger is...Ch. 8.8 - Steam is to be condensed on the shell side of a...Ch. 8.8 - Prob. 82PCh. 8.8 - Prob. 83PCh. 8.8 - Prob. 84PCh. 8.8 - Prob. 85RPCh. 8.8 - Prob. 86RPCh. 8.8 - An aluminum pan has a flat bottom whose diameter...Ch. 8.8 - Prob. 88RPCh. 8.8 - Prob. 89RPCh. 8.8 - A well-insulated, thin-walled, counterflow heat...Ch. 8.8 - Prob. 92RPCh. 8.8 - Prob. 93RPCh. 8.8 - Prob. 94RPCh. 8.8 - Prob. 95RPCh. 8.8 - Nitrogen gas enters a diffuser at 100 kPa and 110C...Ch. 8.8 - Prob. 97RPCh. 8.8 - Steam enters an adiabatic nozzle at 3.5 MPa and...Ch. 8.8 - Prob. 99RPCh. 8.8 - A pistoncylinder device initially contains 8 ft3...Ch. 8.8 - An adiabatic turbine operates with air entering at...Ch. 8.8 - Steam at 7 MPa and 400C enters a two-stage...Ch. 8.8 - Prob. 103RPCh. 8.8 - Steam enters a two-stage adiabatic turbine at 8...Ch. 8.8 - Prob. 105RPCh. 8.8 - Prob. 106RPCh. 8.8 - Prob. 107RPCh. 8.8 - Prob. 108RPCh. 8.8 - Prob. 109RPCh. 8.8 - Prob. 111RPCh. 8.8 - A passive solar house that was losing heat to the...Ch. 8.8 - Prob. 113RPCh. 8.8 - A 4-L pressure cooker has an operating pressure of...Ch. 8.8 - Repeat Prob. 8114 if heat were supplied to the...Ch. 8.8 - Prob. 116RPCh. 8.8 - A rigid 50-L nitrogen cylinder is equipped with a...Ch. 8.8 - Prob. 118RPCh. 8.8 - Prob. 119RPCh. 8.8 - Prob. 120RPCh. 8.8 - Reconsider Prob. 8-120. The air stored in the tank...Ch. 8.8 - Prob. 122RPCh. 8.8 - Prob. 123RPCh. 8.8 - Prob. 124RPCh. 8.8 - Prob. 125RPCh. 8.8 - Prob. 126RPCh. 8.8 - Prob. 127RPCh. 8.8 - Water enters a pump at 100 kPa and 30C at a rate...Ch. 8.8 - Prob. 129RPCh. 8.8 - Prob. 130RPCh. 8.8 - Obtain a relation for the second-law efficiency of...Ch. 8.8 - Writing the first- and second-law relations and...Ch. 8.8 - Prob. 133RPCh. 8.8 - Keeping the limitations imposed by the second law...Ch. 8.8 - Prob. 135FEPCh. 8.8 - Prob. 136FEPCh. 8.8 - Prob. 137FEPCh. 8.8 - Prob. 138FEPCh. 8.8 - A furnace can supply heat steadily at 1300 K at a...Ch. 8.8 - A heat engine receives heat from a source at 1500...Ch. 8.8 - Air is throttled from 50C and 800 kPa to a...Ch. 8.8 - Prob. 142FEPCh. 8.8 - A 12-kg solid whose specific heat is 2.8 kJ/kgC is...
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- Please do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful! Please do not copy other's work,i will be very very grateful!!arrow_forwardPlease do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful! Please do not copy other's work,i will be very very grateful!!arrow_forwardPlease do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful! Please do not copy other's work,i will be very very grateful!!arrow_forward
- (19) Figure Q19 shows a framework consisting of horizontal members 3 m long and vertical members 4 m long. The framework is loaded at joints J and L with downward load forces of 2 kN. The applied forces cause a vertical reaction forces at A and G and no horizontal reaction force. You are asked to find the internal force in member JK - what would be your approach to solve this problem? Explain your solution process and some of your results by filling in the blanks below. 2 kN 2 kN H RAY RAX A K M N B C D E F 3 m 1 RGY 4m Fill in the multiple blanks. Figure Q19 Finding the vertical reactions is the starting point which can be done by taking moments at A and G but since this is symmetrical loading case the vertical reactions can simply be calculated by halving the total loading 4 kN. Ideally, we can solve the problem using the Method of cutting through the members JK, DJ and It would be sensible to select the left-hand side of the diagram as there are less full members and only one force…arrow_forward4m A 72 kN C E B D F 144 kN 3 m 3 m 3 m Figure Q16 Fill in the multiple blanks below. To find the reactions the starting point is to take moments at a suitable node location. Since node unknowns it is the ideal location to first take moments. By taking moments in a clockwise orientation we find a moment of there is an additional moment of 288 kNm from the load at C. From combining all moments together, we can then find the vertical reaction at F which is RFy= place. For best practice, it is a good approach to take moments at has two kNm due to the force load at node B and KN to 1 decimal in order to the find the vertical reaction RAY- Finally, we can sum forces in the horizontal direction to find the reaction RAX = -72 kN, assuming the reaction at A acts left-to-right. After which we can then sum forces in the vertical direction to verify the sum of RAY plus Rgy is the same as the total downwards force which should be KN.arrow_forwardPlease do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful! Please do not copy other's work,i will be very very grateful!!arrow_forward
- 10 kN A B 1m RBY 20 kN/m 30 kN с D E 1m 1m 1m Find the vertical reaction Rgy at B Figure Q18 Find the vertical reaction REY at E Verify the reactions Rgy and REY are valid ✓ Find the Bending Moment value at C You could find the Bending Moment value at B شه A. by finding the area on the Shear Force graph left of B (treating areas underneath the x-axis as negative). B. by taking moments at B. C. by taking moments of all forces left of C. D. by taking moments at E. E. by summing all forces in a vertical direction.arrow_forwardPlease do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful! Please do not copy other's work,i will be very very grateful!!arrow_forward(10) A regular cross-section XXY mm beam, where X=84 m and Y=77 m and 1800 mm long, is loaded from above in the middle with a load of Z=2 kN causing a compressive Bending Stress at the top of the beam and tensile Bending Stress at the bottom of the beam. The beam in addition experiences a tensile end loading in order to reduce the compressive stress in the beam to a near zero value. The configuration of the beam is illustrated in Figure Q10. Calculate the end loading force required in order to reduce total compressive stress experienced in the beam to be near zero? State your answer to the nearest 1 decimal place in terms of kilo-Newtons. X mm Y mm ? KN Z KN Figure Q10 1800 mm ? KNarrow_forward
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