The reason for 1 A to be equivalent to a fraction with denominator 99999 where A is a counting number such that the decimal representation of the fraction 1 A is repeating and the string of repeating digits consists of 5 digits that starts right after the decimal point.

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Answer 1

Question

Chapter 8.6, Problem 15P

(a)

To determine

To explain: The reason for 1A to be equivalent to a fraction with denominator 99999 where A is a counting number such that the decimal representation of the fraction 1A is repeating and the string of repeating digits consists of 5 digits that starts right after the decimal point.

(b)

To determine

To write: The number 99,999 as the product of prime numbers.

(c)

To determine

To find: All the prime numbers A such that 1A has a repeating decimal representation with a 5-digit string of repeating digits.

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Answer 2

Question

Chapter 8.6, Problem 15P

(a)

To determine

To explain: The reason for 1A to be equivalent to a fraction with denominator 99999 where A is a counting number such that the decimal representation of the fraction 1A is repeating and the string of repeating digits consists of 5 digits that starts right after the decimal point.

(b)

To determine

To write: The number 99,999 as the product of prime numbers.

(c)

To determine

To find: All the prime numbers A such that 1A has a repeating decimal representation with a 5-digit string of repeating digits.

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Answer 3

Question

Chapter 8.6, Problem 15P

(a)

To determine

To explain: The reason for 1A to be equivalent to a fraction with denominator 99999 where A is a counting number such that the decimal representation of the fraction 1A is repeating and the string of repeating digits consists of 5 digits that starts right after the decimal point.

(b)

To determine

To write: The number 99,999 as the product of prime numbers.

(c)

To determine

To find: All the prime numbers A such that 1A has a repeating decimal representation with a 5-digit string of repeating digits.

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Answer 4

Question

Chapter 8.6, Problem 15P

(a)

To determine

To explain: The reason for 1A to be equivalent to a fraction with denominator 99999 where A is a counting number such that the decimal representation of the fraction 1A is repeating and the string of repeating digits consists of 5 digits that starts right after the decimal point.

(b)

To determine

To write: The number 99,999 as the product of prime numbers.

(c)

To determine

To find: All the prime numbers A such that 1A has a repeating decimal representation with a 5-digit string of repeating digits.

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Answer 5

Chapter 8.6, Problem 15P

(a)

To determine

To explain: The reason for 1A to be equivalent to a fraction with denominator 99999 where A is a counting number such that the decimal representation of the fraction 1A is repeating and the string of repeating digits consists of 5 digits that starts right after the decimal point.

(b)

To determine

To write: The number 99,999 as the product of prime numbers.

(c)

To determine

To find: All the prime numbers A such that 1A has a repeating decimal representation with a 5-digit string of repeating digits.

Answer 6

Chapter 8.6, Problem 15P

(a)

To determine

To explain: The reason for 1A to be equivalent to a fraction with denominator 99999 where A is a counting number such that the decimal representation of the fraction 1A is repeating and the string of repeating digits consists of 5 digits that starts right after the decimal point.

Answer 7

Chapter 8.6, Problem 15P

(a)

To determine

To explain: The reason for 1A to be equivalent to a fraction with denominator 99999 where A is a counting number such that the decimal representation of the fraction 1A is repeating and the string of repeating digits consists of 5 digits that starts right after the decimal point.

Answer 8

(b)

To determine

To write: The number 99,999 as the product of prime numbers.

Answer 9

(b)

To determine

To write: The number 99,999 as the product of prime numbers.

Answer 10

(c)

To determine

To find: All the prime numbers A such that 1A has a repeating decimal representation with a 5-digit string of repeating digits.

Answer 11

(c)

To determine

To find: All the prime numbers A such that 1A has a repeating decimal representation with a 5-digit string of repeating digits.

Answer 12

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Answer 13

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Answer 14

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Answer 15

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The reason for 1 A to be equivalent to a fraction with denominator 99999 where A is a counting number such that the decimal representation of the fraction 1 A is repeating and the string of repeating digits consists of 5 digits that starts right after the decimal point.

Solution Summary: The author explains that 1A is equivalent to a tion with denominator 99999.

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To explain: The reason for 1A to be equivalent to a fraction with denominator 99999 where A is a counting number such that the decimal representation of the fraction 1A is repeating and the string of repeating digits consists of 5 digits that starts right after the decimal point.

To write: The number 99,999 as the product of prime numbers.

To find: All the prime numbers A such that 1A has a repeating decimal representation with a 5-digit string of repeating digits.

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