Statics and Mechanics of Materials, Student Value Edition (5th Edition)
5th Edition
ISBN: 9780134382890
Author: Russell C. Hibbeler
Publisher: PEARSON
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Chapter 8.6, Problem 15FP
To determine
Find the magnitude of force P.
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Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to find
Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of the
Procedure:
1- Cartesian system, 2D3D,
type of support
2- Free body diagram
3 - Find the support reactions
4- If you find a negative
number then flip the force
5- Find the internal force
3D
∑Fx=0
∑Fy=0
∑Fz=0
∑Mx=0
∑My=0
ΣMz=0
2D
ΣFx=0
ΣFy=0
ΣMz=0
5- Use method of section
and cut the element
where you want to find
the internal force and
keep either side of the
Chapter 8 Solutions
Statics and Mechanics of Materials, Student Value Edition (5th Edition)
Ch. 8.4 - Define a homogeneous material.Ch. 8.4 - Prob. 2FPCh. 8.4 - Prob. 3FPCh. 8.4 - Prob. 4FPCh. 8.4 - Prob. 5FPCh. 8.4 - As the temperature increases the modulus of...Ch. 8.4 - Prob. 7FPCh. 8.4 - Prob. 8FPCh. 8.4 - Prob. 9FPCh. 8.4 - Prob. 10FP
Ch. 8.4 - The material for the 50-mm-long specimen has the...Ch. 8.4 - If the elongation of wire BC is 0.2 mm after the...Ch. 8.4 - A tension test was performed on a steel specimen...Ch. 8.4 - Data taken from a stressstrain test for a ceramic...Ch. 8.4 - Data taken from a stressstrain test for a ceramic...Ch. 8.4 - Prob. 4PCh. 8.4 - The stress-strain diagram for a steel alloy having...Ch. 8.4 - Prob. 6PCh. 8.4 - The rigid beam is supported by a pin at C and an...Ch. 8.4 - The rigid beam is supported by a pin at C and an...Ch. 8.4 - Prob. 9PCh. 8.4 - The stressstrain diagram for an aluminum alloy...Ch. 8.4 - The stressstrain diagram for an aluminum alloy...Ch. 8.4 - Prob. 12PCh. 8.4 - A bar having a length of 5 in. and cross-sectional...Ch. 8.4 - The rigid pipe is supported by a pin at A and an...Ch. 8.4 - The rigid pipe is supported by a pin at A and an...Ch. 8.4 - Prob. 16PCh. 8.4 - The rigid beam is supported by a pin at C and an...Ch. 8.4 - Prob. 18PCh. 8.4 - Prob. 19PCh. 8.6 - A 100 mm long rod has a diameter of 15 mm. If an...Ch. 8.6 - A solid circular rod that is 600 mm long and 20 mm...Ch. 8.6 - Prob. 15FPCh. 8.6 - Prob. 16FPCh. 8.6 - The acrylic plastic rod is 200 mm long and 15 mm...Ch. 8.6 - The plug has a diameter of 30 mm and fits within a...Ch. 8.6 - The elastic portion of the stress-strain diagram...Ch. 8.6 - The elastic portion of the stress-strain diagram...Ch. 8.6 - The brake pads for a bicycle tire arc made of...Ch. 8.6 - The lap joint is connected together using a 1.25...Ch. 8.6 - The lap joint is connected together using a 1.25...Ch. 8.6 - Prob. 27PCh. 8.6 - The shear stress-strain diagram for an alloy is...Ch. 8.6 - Prob. 29PCh. 8 - The elastic portion of the tension stress-strain...Ch. 8 - Prob. 2RPCh. 8 - Prob. 3RPCh. 8 - Prob. 4RPCh. 8 - Prob. 5RPCh. 8 - Prob. 6RPCh. 8 - The stress-strain diagram for polyethylene, which...Ch. 8 - The pipe with two rigid caps attached to its ends...Ch. 8 - Prob. 9RPCh. 8 - Prob. 10RP
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- Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of thearrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forward
- For each system below with transfer function G(s), plot the pole(s) on the s-plane. and indicate whether the system is: (a) "stable" (i.e., a bounded input will always result in a bounded output), (b) "marginally stable," or (c) "unstable" Sketch a rough graph of the time response to a step input. 8 a) G(s) = 5-5 8 b) G(s) = c) G(s) = = s+5 3s + 8 s² - 2s +2 3s +8 d) G(s): = s²+2s+2 3s+8 e) G(s): = s² +9 f) G(s): 8 00 == Sarrow_forwardPlease answer the following question. Include all work and plase explain. Graphs are provided below. "Consider the Mg (Magnesium) - Ni (Nickel) phase diagram shown below. This phase diagram contains two eutectic reactions and two intermediate phases (Mg2Ni and MgNi2). At a temperature of 505oC, determine what the composition of an alloy would need to be to contain a mass fraction of 0.20 Mg and 0.80 Mg2Ni."arrow_forwardThe triangular plate, having a 90∘∘ angle at AA, supports the load PP = 370 lblb as shown in (Figure 1).arrow_forward
- Design a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, ß2 = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. φ 1.236 P2 147.5° 210° 2.138 P1 Figure 1 Xarrow_forwardDesign a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, B₂ = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. 1.236 P2 147.5° 210° P1 Figure 1 2.138 Xarrow_forwardcan you explain how in a coordinate frame transformation: v = {v_n}^T {n-hat} and then it was found that {n-hat} = [C]^T {b-hat} so v_n = {v_n}^T [C]^T {b-hat}, how does that equation go from that to this --> v_n = [C]^T v_barrow_forward
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