Explanation Given: The differential equation is x 3 y ‴ ( x ) + 3 x 2 y ″ ( x ) + 5 x y ′ ( x ) − 5 y ( x ) = 0 Approach: A second-order homogeneous equation in the form a x 2 y ″ ( x ) + b x y ′ ( x ) + c y ( x ) = 0 is called Cauchy - Euler equation, where a ≠ 0 and b and c are real numbers. If the equation has a singular point then it has solution in the form of y = x r . If the roots of equation a r 2 + b r + c = 0 are real such that r = r 1 = r 2 , then general solution is y ( t ) = c 1 e r t + c 2 t e r t If the roots of equation a r 2 + b r + c = 0 are real such that r 1 ≠ r 2 then general solution is y ( t ) = c 1 e r 1 t + c 2 e r 2 t If the roots of equation a r 2 + b r + c = 0 are imaginary in form of r 1 , 2 = α ± β i then general solution is y ( t ) = e a t ( c 1 cos β t + c 2 sin β t ) Calculation: Consider the given problem. x 3 y ‴ ( x ) + 3 x 2 y ″ ( x ) + 5 x y ′ ( x ) − 5 y ( x ) = 0 ... ( 1 ) Let, w ( r , x ) = x r and L is the left hand side of the equation. Differentiate w ( r , x ) = x r upto third derivative. d 3 d r 3 { L [ w ] ( x ) } = d 3 d r 3 x r = d 2 d r 2 r x r − 1 = d d r r ( r − 1 ) x r − 2 = ( r − 2 ) ( r − 1 ) r x r − 3 Substitute ( r − 2 ) ( r − 1 ) r x r − 3 for y ‴ , r ( r − 1 ) x r − 2 for y ″ , r x r − 1 for y ′ and x r for y in equation ( 1 ) .

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ISBN: 9780321977175

Author: Nagle

Publisher: PEARSON CO

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Chapter 8.5, Problem 9E

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The general solution of a differential equation by substitution of y=xr, for x>0.

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Chapter 8.5, Problem 8E

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What is a solution to a differential equation? We said that a differential equation is an equation that describes the derivative, or derivatives, of a function that is unknown to us. By a solution to a differential equation, we mean simply a function that satisfies this description. 2. Here is a differential equation which describes an unknown position function s(t): ds dt 318 4t+1, ds (a) To check that s(t) = 2t2 + t is a solution to this differential equation, calculate you really do get 4t +1. and check that dt' (b) Is s(t) = 2t2 +++ 4 also a solution to this differential equation? (c) Is s(t)=2t2 + 3t also a solution to this differential equation? ds 1 dt (d) To find all possible solutions, start with the differential equation = 4t + 1, then move dt to the right side of the equation by multiplying, and then integrate both sides. What do you get? (e) Does this differential equation have a unique solution, or an infinite family of solutions?

these are solutions to a tutorial that was done and im a little lost. can someone please explain to me how these iterations function, for example i Do not know how each set of matrices produces a number if someine could explain how its done and provide steps it would be greatly appreciated thanks.

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The general solution of a differential equation by substitution of y = x r , for x > 0 .

Solution Summary: The author explains the general solution of a differential equation by substitution of y=xr.

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The general solution of a differential equation by substitution of y = x r , for x &gt; 0 .

Solution Summary: The author explains the general solution of a differential equation by substitution of y=xr.

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Chapter 8 Solutions

The general solution of a differential equation by substitution of y = x r , for x > 0 .

To find:

The general solution of a differential equation by substitution of y=xr, for x>0.