A weak earthquake occurred roughly 9 km south and 12 km west of the center of Hawthorne, Nevada. The quake could be felt 16 km away. Suppose that the origin of a map is placed at the center of Hawthorne with the positive x -axis pointing east and the positive y -axis pointing north. a. Find an inequality that describes the points on the map for which the earthquake could be felt. b. Could the earthquake be felt at the center of Hawthorne?
A weak earthquake occurred roughly 9 km south and 12 km west of the center of Hawthorne, Nevada. The quake could be felt 16 km away. Suppose that the origin of a map is placed at the center of Hawthorne with the positive x -axis pointing east and the positive y -axis pointing north. a. Find an inequality that describes the points on the map for which the earthquake could be felt. b. Could the earthquake be felt at the center of Hawthorne?
A weak earthquake occurred roughly
9
km
south and
12
km
west of the center of Hawthorne, Nevada. The quake could be felt
16
km
away. Suppose that the origin of a map is placed at the center of Hawthorne with the positive
x
-axis
pointing east and the positive
y
-axis
pointing north.
a. Find an inequality that describes the points on the map for which the earthquake could be felt.
b. Could the earthquake be felt at the center of Hawthorne?
Given lim x-4 f (x) = 1,limx-49 (x) = 10, and lim→-4 h (x) = -7 use the limit properties
to find lim→-4
1
[2h (x) — h(x) + 7 f(x)] :
-
h(x)+7f(x)
3
O DNE
17. Suppose we know that the graph below is the graph of a solution to dy/dt = f(t).
(a) How much of the slope field can
you sketch from this information?
[Hint: Note that the differential
equation depends only on t.]
(b) What can you say about the solu-
tion with y(0) = 2? (For example,
can you sketch the graph of this so-
lution?)
y(0) = 1
y
AN
(b) Find the (instantaneous) rate of change of y at x = 5.
In the previous part, we found the average rate of change for several intervals of decreasing size starting at x = 5. The instantaneous rate of
change of fat x = 5 is the limit of the average rate of change over the interval [x, x + h] as h approaches 0. This is given by the derivative in the
following limit.
lim
h→0
-
f(x + h) − f(x)
h
The first step to find this limit is to compute f(x + h). Recall that this means replacing the input variable x with the expression x + h in the rule
defining f.
f(x + h) = (x + h)² - 5(x+ h)
=
2xh+h2_
x² + 2xh + h² 5✔
-
5
)x - 5h
Step 4
-
The second step for finding the derivative of fat x is to find the difference f(x + h) − f(x).
-
f(x + h) f(x) =
= (x²
x² + 2xh + h² -
])-
=
2x
+ h² - 5h
])x-5h) - (x² - 5x)
=
]) (2x + h - 5)
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