Explanation Given: The differential equation is x 2 y ″ ( x ) + 6 x y ′ ( x ) + 6 y ( x ) = 0 . Approach: A second-order homogeneous equation in the form a x 2 y ″ ( x ) + b x y ′ ( x ) + c y ( x ) = 0 is called Cauchy-Euler equation, here a ≠ 0 and b , c are real numbers. If the equation has a singular point then it has solution in the form of y = x r . If the roots of equation a r 2 + b r + c = 0 are real such that r = r 1 = r 2 , then general solution is y ( t ) = c 1 e r t + c 2 t e r t If the roots of equation a r 2 + b r + c = 0 are real such that r 1 ≠ r 2 then general solution is y ( t ) = c 1 e r 1 t + c 2 e r 2 t If the roots of equation a r 2 + b r + c = 0 are imaginary in form of r 1 , 2 = α ± β i then general solution is y ( t ) = e a t ( c 1 cos β t + c 2 sin β t ) Calculation: Consider the given problem. x 2 y ″ ( x ) + 6 x y ′ ( x ) + 6 y ( x ) = 0 ... ( 1 ) Let, w ( r , x ) = x r and L is the left hand side of the equation. Differentiate w ( r , x ) = x r upto second derivative.

Fundamentals of Differential Equations and Boundary Value Problems

7th Edition

ISBN: 9780321977106

Author: Nagle, R. Kent

Publisher: Pearson Education, Limited

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The general solution of a differential equation by substitution of y = x r for x > 0 .

To find:

The general solution of a differential equation by substitution of y=xr for x>0.