Explanation Given: The differential equation is 2 ( x − 3 ) 2 y ″ ( x ) + 5 ( x − 3 ) y ′ ( x ) − 2 y ( x ) = 0 Approach: A second-order homogeneous equation in the form a x 2 y ″ ( x ) + b x y ′ ( x ) + c y ( x ) = 0 is called Cauchy - Euler equation, where a ≠ 0 and b and c are real numbers. If the equation has a singular point then it has solution in the form of y = x r . If the roots of equation a r 2 + b r + c = 0 are real such that r = r 1 = r 2 , then general solution is y ( t ) = c 1 e r t + c 2 t e r t If the roots of equation a r 2 + b r + c = 0 are real such that r 1 ≠ r 2 then general solution is y ( t ) = c 1 e r 1 t + c 2 e r 2 t If the roots of equation a r 2 + b r + c = 0 are imaginary in form of r 1 , 2 = α ± β i then general solution is y ( t ) = e α t ( c 1 cos β t + c 2 sin β t ) Calculation: Consider the given problem. 2 ( x − 3 ) 2 y ″ ( x ) + 5 ( x − 3 ) y ′ ( x ) − 2 y ( x ) = 0 … ( 1 ) Let, w ( r , x ) = ( x − c ) r and L is the left hand side of the equation. Differentiate w ( r , x ) = ( x − c ) r up to third derivative. d 2 d r 2 { L [ w ] ( x ) } = d 2 d r 2 ( x − 3 ) r = d d r r ( x − 3 ) x r − 1 = r ( r − 1 ) ( x − 3 ) x r − 2 Substitute r ( r − 1 ) ( x − 3 ) x r − 2 for y ″ , r ( x − 3 ) x r − 1 for y ′ and ( x − 3 ) r for y in equation (1)

Fundamentals of Differential Equations and Boundary Value Problems

7th Edition

ISBN: 9780321977106

Author: Nagle, R. Kent

Publisher: Pearson Education, Limited

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The general solution of a differential equation by substitution of y = ( x − c ) r , for x > c .

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The general solution of a differential equation by substitution of y = ( x − c ) r , for x &gt; c .

Solution Summary: The author explains the general solution of a differential equation by substitution of y=(x-c)r, for x>c.

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To find: The general solution of a differential equation by substitution of y=(x−c)r, for x>c.

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The general solution of a differential equation by substitution of y = ( x − c ) r , for x > c .

To find:

The general solution of a differential equation by substitution of y=(x−c)r, for x>c.