EBK ELECTRIC CIRCUITS
EBK ELECTRIC CIRCUITS
11th Edition
ISBN: 9780134747224
Author: Riedel
Publisher: PEARSON CUSTOM PUB.(CONSIGNMENT)
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Chapter 8.4, Problem 8AP
To determine

Find the expression of i(t) for t0 in the given circuit.

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MY code is experiencing a problem as I want to show both the magnitude ratio on low pass, high pass, and bandbass based on passive filters: Code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2*pi*f; % Angular frequency   % Parameters for the filters (you can modify these) R = 1e3; % Resistance in ohms (1 kOhm) C = 1e-6; % Capacitance in farads (1 uF) L = 10e-3; % Inductance in henries (10 mH)   % Transfer function for Low-pass filter: H_low = 1 / (1 + jωRC) H_low = 1 ./ (1 + 1i*w*R*C);   % Transfer function for High-pass filter: H_high = jωRC / (1 + jωRC) H_high = 1i*w*R*C ./ (1 + 1i*w*R*C);   % Transfer function for Band-pass filter: H_band = jωRC / (1 + jωL/R + jωRC) H_band = 1i*w*R*C ./ (1 + 1i*w*L/R + 1i*w*R*C);   % Plot magnitude responses figure; subplot(3,1,1); semilogx(f, 20*log10(abs(H_low))); % Low-pass filter title('Magnitude Response of Low-pass Filter'); xlabel('Frequency (Hz)'); ylabel('Magnitude (dB)'); grid…
*10. For the network of Fig. 7.83, determine: a. Ip. b. VDS. c. VD. d. Vs. 20 V 2.2 ΚΩ ID -4 V IDSS = 4.5 mA VDS Vp = -5V 0.68 ΚΩ
4. a. Determine VDs for VGS = 0 V and ID = 6 mA using the characteristics of Fig. 6.11. b. Using the results of part (a), calculate the resistance of the JFET for the region ID = 0 to 6 mA for VGS = 0 V. c. Determine VDs for VGS = -1 V and ID = 3 mA. d. Using the results of part (c), calculate the resistance of the JFET for the region ID = 0 to 3 mA for VGS = -1 V. e. Determine VDs for VGS = -2 V and ID = 1.5 mA. f. Using the results of part (e), calculate the resistance of the JFET for the region ID 1.5 mA for VGS = -2 V. g. Defining the result of part (b) as ro, determine the resistance for VGS Eq. (6.1) and compare with the results of part (d). = 0 to = -1 V using h. Repeat part (g) for VGS = -2 V using the same equation, and compare the results with part (f). i. Based on the results of parts (g) and (h), does Eq. (6.1) appear to be a valid approximation?

Chapter 8 Solutions

EBK ELECTRIC CIRCUITS

Ch. 8 - Prob. 2PCh. 8 - Prob. 3PCh. 8 - Prob. 4PCh. 8 - Prob. 5PCh. 8 - Prob. 6PCh. 8 - The natural response for the circuit shown in Fig....Ch. 8 - The natural voltage response of the circuit in...Ch. 8 - The voltage response for the circuit in Fig. 8.1...Ch. 8 - Prob. 10PCh. 8 - Design a parallel RLC circuit (see Fig. 8.1) using...Ch. 8 - Prob. 12PCh. 8 - The initial value of the voltage υ in the circuit...Ch. 8 - Prob. 14PCh. 8 - The resistor in the circuit of Fig. P8.14 is...Ch. 8 - Prob. 16PCh. 8 - The switch in the circuit of Fig. P8.17 has been...Ch. 8 - The inductor in the circuit of Fig. P8.17 is...Ch. 8 - The inductor in the circuit of Fig. P8.17 is...Ch. 8 - Prob. 20PCh. 8 - Prob. 21PCh. 8 - Prob. 22PCh. 8 - Prob. 23PCh. 8 - Prob. 24PCh. 8 - Prob. 25PCh. 8 - Prob. 26PCh. 8 - The switch in the circuit in Fig. P8.27 has been...Ch. 8 - For the circuit in Fig. P8.27, find υo for t ≥...Ch. 8 - The switch in the circuit in Fig. P8.29 has been...Ch. 8 - There is no energy stored in the circuit in Fig....Ch. 8 - For the circuit in Fig. P8.30, find υo for t ≥...Ch. 8 - Prob. 32PCh. 8 - Prob. 33PCh. 8 - Prob. 34PCh. 8 - Switches 1 and 2 in the circuit in Fig. P8.35 are...Ch. 8 - The switch in the circuit in Fig. P8.36 has been...Ch. 8 - Prob. 37PCh. 8 - Prob. 38PCh. 8 - In the circuit in Fig. P8.39, the resistor is...Ch. 8 - The initial energy stored in the 50 nF capacitor...Ch. 8 - Prob. 41PCh. 8 - Find the voltage across the 80 nF capacitor for...Ch. 8 - Design a series RLC circuit (see Fig. 8.3) using...Ch. 8 - Change the resistance for the circuit you designed...Ch. 8 - Prob. 45PCh. 8 - Prob. 46PCh. 8 - Prob. 47PCh. 8 - The switch in the circuit shown in Fig. P8.48 has...Ch. 8 - Prob. 49PCh. 8 - The initial energy stored in the circuit in Fig....Ch. 8 - The resistor in the circuit shown in Fig. P8.50 is...Ch. 8 - The resistor in the circuit shown in Fig. P8.50 is...Ch. 8 - The two switches in the circuit seen in Fig. P8.53...Ch. 8 - Prob. 54PCh. 8 - Prob. 55PCh. 8 - The circuit parameters in the circuit of Fig....Ch. 8 - Prob. 57PCh. 8 - Prob. 58PCh. 8 - Prob. 59PCh. 8 - Prob. 60PCh. 8 - Prob. 61PCh. 8 - Derive the differential equation that relates the...Ch. 8 - The voltage signal of Fig. P8.63(a) is applied to...Ch. 8 - The circuit in Fig. P8.63 (b) is modified by...Ch. 8 - Prob. 65PCh. 8 - Prob. 66PCh. 8 - Prob. 67PCh. 8 - Prob. 68P
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