Explanation Given: The equation, ( x − 10 x ) 2 + 6 ( x − 10 x ) − 27 = 0 . Formula used: The zero-product principle: If a × b = 0 then either a = 0 or b = 0 or both a a n d b are zero. Calculation: Let, u = ( x − 10 x ) Replace ( x − 10 x ) with u , Then, u 2 + 6 u − 27 = 0 Factor the quadratic equation, ( u − 3 ) ( u + 9 ) = 0 Apply the zero-product principle, u − 3 = 0 or u + 9 = 0 Solve for u , u = 3 or u = − 9 Replace u with ( x − 10 x ) , ( x −

Intermediate Algebra for College Students Access Card Package (7th Edition) (Blitzer Developmental Algebra Series)

7th Edition

ISBN: 9780134189017

Author: Robert F. Blitzer

Publisher: PEARSON

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Chapter 8.4, Problem 32E

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To calculate: The solution of equation,(x−10x)2+6(x−10x)−27=0, by making an appropriate substitution.

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Chapter 8.4, Problem 31E

Chapter 8.4, Problem 33E

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Chapter 8 Solutions

Intermediate Algebra for College Students Access Card Package (7th Edition) (Blitzer Developmental Algebra Series)

Ch. 8.1 - Check Point 1 Solve: . Ch. 8.1 - Prob. 2CP Ch. 8.1 - Prob. 3CP Ch. 8.1 - Prob. 4CP Ch. 8.1 - Prob. 5CP Ch. 8.1 - Prob. 6CP Ch. 8.1 - Prob. 7CP Ch. 8.1 - Prob. 8CP Ch. 8.1 - Prob. 9CP Ch. 8.1 - Prob. 10CP

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The solution of equation, ( x − 10 x ) 2 + 6 ( x − 10 x ) − 27 = 0 , by making an appropriate substitution.

Solution Summary: The author calculates the solution of the given equation, (x-10x)2+6

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To calculate: The solution of equation,(x−10x)2+6(x−10x)−27=0, by making an appropriate substitution.

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Chapter 8 Solutions