Concept explainers
(a)
Conversion of hexadecimal numbers B70905.F816 to a binary numbers.

Answer to Problem 1A
Binary numbers is 101101110000100100000101.111112.
Explanation of Solution
Given information:
A hexadecimal numbers B70905.F816.
Calculation:
Binary number system uses the number 2 as its base. Therefore, it has 2 symbols: The numbers are 0 and 1.
And a hexadecimal number system uses the number 16 as its base i.e. it has 16 symbols, hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A,B,C,D,E and F.
Binary numbers are represented as from hexadecimal number
Hexadecimal | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
Decimal | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
Binary | 0000 | 0001 | 0010 | 0011 | 0100 | 0101 | 0110 | 0111 |
Hexadecimal | 8 | 9 | A | B | C | D | E | F |
Decimal | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 |
Binary | 1000 | 1001 | 1010 | 1011 | 1100 | 1101 | 1110 | 1111 |
Each hexadecimal digit consists of 4 binary digits.
For example hexadecimal number 9 is equal to binary number 1001.
For converting hexadecimal numbers into binary numbers write down the hexadecimal numbers and represent each hexadecimal digit by its binary digit from the table.
Then combine all the digits together.
Same process follows for integer as well as fractional part.
Hexadecimal digits are equal to the summation of 2n where n = 0, 1, 2 and 3 (position from right)
For example 9 = 23+20; in this example 21 and 22 is not exist so at position 1 and 2 binary digit is zero and at position 0 and 3 binary digit is one; so binary of this digit "9" is
1 0 0 1
↓ ↓ ↓ ↓
23 22 21 20
(b)
Conversion of hexadecimal numbers B70905.F816 to a decimal numbers.

Answer to Problem 1A
Decimal numbers is 11995397.9687510.
Explanation of Solution
Given information:
A hexadecimal numbers B70905.F816.
Calculation:
Decimal number system uses the number 10 as its base. Therefore, it has 10 symbols: The numbers from 0 to 9; namely 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.
And a hexadecimal number system uses the number 16 as its base i.e. it has 16 symbols, 10 as decimal symbol, the extra needed 6 digits are represented by the first 6 letters of english alphabet. Hence, hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 A,B,C,D,E and F.
Hexadecimal numbers are represented as
Hexadecimal | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | A | B | C | D | E | F |
Decimal | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 |
Conversion of hexadecimal number into decimal number the following steps are used
For integer part
Ones place is multiply with 160
Tens place is multiply with 161
hundreds place is multiply with 162
and so on...
and for fractional part
Tenths place is multiply by 16-1
hundredths is multiply place by 16-2
and so on...
Now converting hexadecimal number into decimal number in tabular form
Place | One lakh | Ten thousands | Thousands | Hundreds | Tens | Ones | Decimal point | Tens | Hundreds |
Hexadecimal number | B | 7 | 0 | 9 | 0 | 5 | . | F | 8 |
Multiplier | 165 | 164 | 163 | 162 | 161 | 160 | . | 16-1 | 16-2 |
Decimal number | B×165 | 7×164 | 0×163 | 9×162 | 0×161 | 5×160 | F×16-1 | 8×16-2 |
So decimal number is
Want to see more full solutions like this?
Chapter 84 Solutions
EBK MATHEMATICS FOR MACHINE TECHNOLOGY
- μ=1 r = 30 mm 500 mm a 7000 mm b 7000 mm C 500 mmarrow_forwardPhil has systematically contributed $3000 to his RRSP at the beginning of every three months for the past 17 years.If the RRSP has earned 8.8% compounded quarterly, what is the value of Phil’s RRSP today? (Do not round intermediate calculations and round your final answer to 2 decimal places.)The value of the RRSP today $arrow_forwardAnswer this pleasearrow_forward
- Can you prove that P(a,b) >= P(a',b) for a >= a' >= b >= 0arrow_forwardFigure 1 Simulation structure diagram for a turbine cold-end system. approximated by the two fourth degree polynomial equations as follows: The turbine "cold-and" system generally consists of turbine exhaust and condenser, and cooling tower (Fig. 1). For a 250 MW unit, the turbine performance data with the maximum steam throttle flow can be NHR NEW NHR Turbine and NHR = −45.19(CP)* + 420(CP)® – 1442(CP)2 + 2248(CP) +6666 (a) NKW = 4,883(CP)* – 44,890(CP)3 + 152,600(CP)2 – 231,500(CP) + 383,400. (b) The condenser and mechanical-draft cooling tower have the performance equations, respectively, CP 1.6302-0.50095 x 10-1 (CWT) OP Coupling 1 Condenser CR WFR CWT Coupling 2 WST Cooling Tower CR System Boundary 2 (The circulating water flow is assumed to flow at the rate of 145,000 gpm.) In addition to the given performance equations give above, we also need two coupling equations to complete the mathematical model for this cooling system. The first equation is the coupling between the…arrow_forwardCan you evaluate the following for n >0?arrow_forward
- Mathematics For Machine TechnologyAdvanced MathISBN:9781337798310Author:Peterson, John.Publisher:Cengage Learning,Algebra: Structure And Method, Book 1AlgebraISBN:9780395977224Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. ColePublisher:McDougal LittellHolt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGAL
- College Algebra (MindTap Course List)AlgebraISBN:9781305652231Author:R. David Gustafson, Jeff HughesPublisher:Cengage LearningAlgebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:CengageGlencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill




