Electrical Motor Controls For Integrated Systems: Applications Manual
5th Edition
ISBN: 9780826912299
Author: Gary J. Rockis;glen A. Mazur
Publisher: American Technical Publishers
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Chapter 8.3, Problem 4CP
To determine
To explain: Can reed relay be manually operated.
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4- A 75 KW, 250 V shunt generator has R₁ = 0.03 2 and RF =50 2. The generator has 6 poles and is lap wound with totally 400
conductors. The generator runs at 600 rpm on full load. The bore of the machine is 42 cm (in diameter), its axial length is 28 cm
and each pole subtends an angle of 54 °.
Field
pole
a)
b)
c)
Find the airgap flux density. (10 pt)
Find the induced voltage under full load. (10 pt)
Find the average number of active conductors. (5 pts)
28 cm
21 cm
60°
Armature
a) The phase currents in a delta - connected three-phase load are as follows: between the
red and yellow lines, 60 A at p.f. 0.9 leading; between the yellow and blue lines, 40 A at
0.95 p.f lagging; between the blue and red lines, 50 A at p.f. 0.8 lagging. The supply
voltage is 240 V. Draw a labeled diagram of the circuit and calculate the line currents.
Note: Use VRY as the reference phasor.
b) The two-wattmeter method is used to measure the total power drawn by the load in 1 (a)
above. Wattmeter one has its current coil connected in the yellow line and its voltage coil
connected between the yellow and red lines. Calculate:
i. The power measured by each wattmeter.
ii. The power factor of the load.
QUESTION NO. 1
a) State Lenz Law
b) Explain Flux density
c) A wire, 100 mm long, is moved at a uniform speed of 4 m/s at right angles to its
length and to a uniform magnetic field. Calculate the density of the field if the e.m.f.
generated in the wire is 0.15 V. If the wire forms part of a closed circuit having a
total resistance of 0.04 2, calculate the force on the wire in newtons.
Chapter 8 Solutions
Electrical Motor Controls For Integrated Systems: Applications Manual
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- Need Handwritten solution not using chatgt or AIarrow_forward2. Suppose G₁(s) = (s+2) G₂(s) = (s-3) C(s) Find the transfer function G(s): for each of the following three configurations R(s) shown in Figure 1. Note (a) is a cascaded (series) system, (b) is a parallel system, and (c) is a feedback (closed-loop) system. € (c) C(s) R(s) G₁(s) G2(5) G₁(s) R(s) C(s) G2(s) C(s) R(s) G₁(s) G₂(s) Figure 1arrow_forwardDetermine the transformer's active power losses and primary voltage (Figure 1). The busbar's voltage at the transformer's secondary side is 20.5 kV. Load P is 6 MW, and the power factor is 0.95ind.arrow_forward
- Select a short-circuit withstanding (1-second short circuit length) cable for Feeder 1 in Figure 1. Values for cables are given in Table 1. The voltage of the supplying network is now 115 kV and the short-circuit power of the supplying network is 2000 MVA. Table 1. Technical information of 3-phase cables (10 kV and 20 kV) Product's name EA-number Structural information 20KV 20KV 20 KV 0624250 0624252 0624253 0624254 AHKAMK-W AHKAMKW AHKAMKWAHKAMKW AHKAMKW AHKAMKW AHKAMKW 3x50Al+35Cu 3x95 Al. 35Cu 3x120Al. 35Cu 3x150Al+35Cu 3x185Al+35Cu 3x240A1+70 Cu 3x300Al+70Cu 20kV 20kV 20 kV (8) 20KV 0624255 0624257 0624256 Diameter of conductor Diameter of out-most circle Cable's outer diameter Mass Delivery information Standard length Delivery reel mm 8.0 11.3 12.7 14.1 15.7 18.1 20.3 mm 28 32 34 35 37 40 43 mm 64 71 74 76 80 89 94 aluminium kg/km 510 910 1100 1350 1650 2200 2700 сорраг kg/km 305 305 305 305 305 600 600 cable kg/km 2350 3100 3450 3800 4300 5500 6250 E 500 500 500 500 500 500 500…arrow_forwardA three-phase 20 kV medium-voltage line is 10 km. Resistance is 0.252 2/km and reactance is 0.128 92/km (inductive). Voltage at the beginning of line is 21.0 kV. At the end of the line is loading P = 2.5 MW with power factor 0.92ind. Draw 1-phase equivalent diagram and calculate line voltage at the end the of line, active and reactive power at the beginning of the line and power losses of the line.arrow_forwardA three-phase 20 kV medium-voltage line is 10 km. Resistance is 0.365 2/km and reactance is 0.363 2/km (inductive). Voltage at the beginning of line is 20.5 kV. At the end of the line is loading P= 800 kW with power factor 0.95ind. Draw 1-phase equivalent diagram and calculate load current, line voltage at the end the of line, voltage drop and power losses of the line.arrow_forward
- 6. Answer the following questions. Take help from ChatGPT to answer these questions (if you need). Write the answers briefly using your own words with no more than two sentences, and make sure you check whether ChatGPT is giving you the appropriate answers in our context. A) What is a model in our context? B) What is an LTI system? C) What are the three forms of model we have used in the class so far to represent an LTI system? Among the above three forms, which forms can still be used to represent a nonlinear system?arrow_forward5. Consider the following block diagram of a system in the Figure 4. Y₁(s) G₁ G2. R(s) C(s) Y₂(s) G3 G4 Figure 4 The models of the blocks G1, G2, G3 and G4 are represented by a differential equation, transfer function, state-space form, and impulse response as the followings. dy1 G₁: +2y₁ = 3r(t) dt 1 G2: G₂(s) = S+3 G3: x=2x+r, y2=3x-r G4: h(t)=8(t) + et 1(t) Find the simplified expression of the overall transfer function of the system i.e., G(s) = Note for G3 block, you may need to use the formula H(s) = C (sI - A)-¹ B+ D. C(s) R(s)arrow_forward4. Simplify the block diagram in Figure 3 and find the closed-loop transfer function G(s) = C(s) R(s) G₁ R(s) Figure 3 C(s) G2 H₁ H₂arrow_forward
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