Chapter 8.3, Problem 37E

(a)

To determine

To find: The distance travelled by the ball that is thrown by Player A and Player B.

Answer to Problem 37E

The distance travelled by the ball that is thrown by Player A and Player B is $10.4\text{m}\text{\&}9.2\text{m}$ , respectively.

Explanation of Solution

Given information: The following graph is been given:

  

Formula used: $d=\sqrt{{\left(x_2-x_1\right)}^2+{\left(y_2-y_1\right)}^2}$

Calculation: Since Player A throws balls to Player B and similarly, Player B throws to Player C.

Hence, the distance of balls goes that is thrown by Player A.

  $\begin{array}{l}d=\sqrt{{\left(8-18\right)}^2+{\left(4-7\right)}^2}\\ =\sqrt{{\left(-10\right)}^2+{\left(-3\right)}^2}\\ =\sqrt{109}\\ =10.4\text{m}\end{array}$

Similarly, the distance of balls goes that is thrown by Player B.

  $\begin{array}{l}d=\sqrt{{\left(18-24\right)}^2+{\left(7-14\right)}^2}\\ =\sqrt{{\left(-6\right)}^2+{\left(-7\right)}^2}\\ =\sqrt{36+49}\\ =9.2\text{m}\end{array}$

(b)

To determine

To find: The distance travelled by the ball that is thrown by Player A to Player C.

Answer to Problem 37E

The distance travelled by the ball that is thrown by Player A to Player C is $18.9\text{m}$ respectively.

Explanation of Solution

Given information: The following graph is been given:

  

Formula used: $d=\sqrt{{\left(x_2-x_1\right)}^2+{\left(y_2-y_1\right)}^2}$

Calculation: Since Player A throws balls to Player C, hence, the distance of balls goes that is thrown by Player A.

  $\begin{array}{l}d=\sqrt{{\left(8-24\right)}^2+{\left(4-14\right)}^2}\\ =\sqrt{{\left(-16\right)}^2+{\left(-10\right)}^2}\\ =\sqrt{356}\\ =18.9\text{m}\end{array}$