Chapter 8.2, Problem 25E

To determine

To find: The length of abdomen and thorax.

Answer to Problem 25E

Abdomen length is $\frac{1}{2}$ more than the length of thorax.

Abdomen is $\frac{9}{7}$ times longer than thorax.

Explanation of Solution

Given information: By using ruler, we estimate the length of the abdomen and thorax to the nearest $\frac{1}{4}$ inch.

  

Calculation: The length of the abdomen:

  $\begin{array}{l}\Rightarrow 2\frac{1}{4}-0=2\frac{1}{4}\\ \therefore 2\frac{1}{4}=\frac{9}{4}\end{array}$

Similarly the length of the thorax:

  $\begin{array}{l}\Rightarrow 4-2\frac{1}{4}=4-\frac{9}{4}\\ =\frac{16-9}{4}\\ =\frac{7}{4}\end{array}$

Hence, the length of the abdomen that is more than thorax’s length:

  $\begin{array}{l}\Rightarrow \frac{9}{4}-\frac{7}{4}=\frac{2}{4}\\ =\frac{1}{2}\end{array}$

Hence, the length of the abdomen is multiple of thorax’s length:

  $\Rightarrow \frac{\frac{9}{4}}{\frac{7}{4}}=\frac{9}{7}$